Nit*_*bra 1 sql sql-server sql-server-2012
我试图在以下查询中计算运行总计
select
a.ICode, MONTH(a.VDate), YEAR(a.vdate)
, sum(isnull(a.qty, 0))
, sum(isnull(a.qty, 0)) OVER (partition by a.icode order by a.icode) AS 'total'
from
t_Stock as a
group by
a.ICode, MONTH(a.VDate), YEAR(a.vdate)
order by
a.icode, YEAR(a.vdate), MONTH(a.VDate)
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但我收到一个错误:
消息8120,级别16,状态1,行3
列"t_Stock.Qty"在选择列表中无效,因为它不包含在聚合函数或GROUP BY子句中.
为什么' t_Stock.Qty'需要在GROUP BY子句中,因为我已经在使用聚合函数(Sum(a.Qty))?
一些演示数据:
icode vtype qty vdate
32114 Sales -2 2013-06-03 18:09:17.953
33459 Sales -1 2013-06-03 19:39:59.843
34446 Sales -1 2013-06-03 20:46:17.030
39914 Tra -3 2014-01-07 13:02:31.000
30899 Sales -1 2013-06-04 11:48:06.267
25676 Sales -3 2013-06-04 17:34:01.470
32126 Sales -1 2013-06-04 18:12:44.267
34688 Sales -1 2013-06-04 18:40:52.750
31550 Sales -1 2013-06-04 19:26:40.937
32795 Sales -1 2013-06-05 12:03:00.250
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使用带聚合的窗口函数时,实际上需要嵌套结果.以下是您应该使用的查询版本:
select a.ICode, MONTH(a.VDate), YEAR(a.vdate),
sum(isnull(a.qty, 0)),
sum(sum(isnull(a.qty, 0))) OVER (partition by a.icode order by a.icode) AS total
from t_Stock a
group by a.ICode, MONTH(a.VDate), YEAR(a.vdate)
order by a.icode, YEAR(a.vdate), MONTH(a.VDate);
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我不确定你打算怎么做.具有order by包含相同的值partition by是不寻常的.我希望这样的事情:
select a.ICode, MONTH(a.VDate), YEAR(a.vdate),
sum(isnull(a.qty, 0)),
sum(sum(isnull(a.qty, 0))) OVER (partition by a.icode
order by year(a.vdate), month(a.vdate)
) AS total
from t_Stock a
group by a.ICode, MONTH(a.VDate), YEAR(a.vdate)
order by a.icode, YEAR(a.vdate), MONTH(a.VDate);
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