错误:格式%d期望类型为int,但参数2的类型为double(*)(int,int)

Question

我似乎无法在我的printf语句中弄清楚这个错误.无论何时我将格式说明符从整数更改为浮点数,反之亦然,我只是得到相同的错误.

     error: format â%fâ expects type âdoubleâ, but argument 2 has type âdouble (*)(int,     int)â

这是我的代码中的那一部分

void outputScores(int x, int y)
{
if(((x&y)>=1) && ((x&y)<=20))
{
printf("------------------------------\n");
printf("\n");
printf("Field: %d,%d\n",x,y);
printf("\n");
printf("Soil quality: %f\n",soilQuality);
printf("Sun exposure: %d\n",sunExposure);
printf("Irrigation exposure: %d\n",irrigationExposure);
printf("\n");
printf("Estimated yield: %d\n",estimatedYield);
printf("Estimated quality: %d\n",estimatedQuality);
printf("Time to harvest: %d\n",harvestTime);
printf("\n");
printf("Overall Score: %f\n",fieldScore);
printf("\n");
printf("------------------------------\n");
}
else
{
printf("Field %d, %d is invalid!\n",x,y);
}
return;
}

这是功能

 double soilQuality(int x, int y)
 {
 if((x>=1) && (x<=20) && (y>=1) && (y<=20))
 {
 if((x+y)%2==1)
 {
 int soilQuality=(1+(sqrt((x-10)*(x-10))+((y-10)*(y-10))));
 return soilQuality;
 }
 else
 {
 int soilQuality=(1+((abs(x-10)+abs(y-10))/2));
 return soilQuality;
 }
 }
 else
 {
 return -1;
 }
 }

Answer 1

在printf(),%f期望a double,但你给它一个指向类型函数的指针double (*)(int, int).

所以改变

printf("Soil quality: %f\n",soilQuality);

至

printf("Soil quality: %f\n",soilQuality(x, y));

然后再试一次.