我有一个名为 $filtes 的对象数组,如下所示:
Array
(
[0] => stdClass Object
(
[title] => Type
[alias] => type
[id] => 14
[parent_id] => 9
[subs] => Array
(
[0] => stdClass Object
(
[title] => car
[alias] => car
[id] => 15
[parent_id] => 14
)
)
)
[1] => stdClass Object
(
[title] => Model
[alias] => model
[id] => 18
[parent_id] => 9
[subs] => Array
(
[0] => stdClass Object
(
[title] => XF
[alias] => xf
[id] => 19
[parent_id] => 18
)
[1] => stdClass Object
(
[title] => XJ
[alias] => xj
[id] => 20
[parent_id] => 18
)
[2] => stdClass Object
(
[title] => XK
[alias] => xk
[id] => 21
[parent_id] => 18
)
[3] => stdClass Object
(
[title] => F-TYPE
[alias] => f-type
[id] => 22
[parent_id] => 18
)
)
)
[2] => stdClass Object
(
[title] => Condition
[alias] => condition
[id] => 24
[parent_id] => 9
[subs] => Array
(
[0] => stdClass Object
(
[title] => new
[alias] => new
[id] => 24
[parent_id] => 9
)
)
)
)
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检查 $filters[$i]->title 和 $filters[$i]->subs[$j]->title 中是否存在某个单词的最佳做法是什么。在此检查中,速度非常重要。
创建一个简单的递归函数:
function myArrayContainsWord(array $myArray, $word) {
foreach ($myArray as $element) {
if ($element->title == $word ||
(!empty($myArray['subs']) && myArrayContainsWord($myArray['subs'], $word)) {
return true;
}
}
return false;
}
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然后像这样调用它:
if (myArrayContainsWord($filtes, $title)) {
...
}
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