如何找到列的第n个最高值？

Question

是否有类似于的命令:

• 2nd highest salary from tbl_salary 要么

• 4th highest salary from tbl_salary ？

我见过:

select salary
from tbl_salary t
where &n = (
    select count(salary) 
    from(
        select distinct salary
        from tbl_salary
    )where t.salary<=salary
);

它是如何工作的？

有没有其他简单的方法来获得结果？

Answer 1

如果是基本查询,那么只需使用LIMIT:

-- get the 4th highest salary
SELECT salary FROM tbl_salary
ORDER BY salary DESC
LIMIT 3,1

Answer 2

select * from employee order by salary desc limit 1,1

说明: limit x,y

• x:要从中开始显示记录的行偏移量.对于第n个记录,它将是n-1.
• y:要显示的记录数.(在这种情况下总是1)

Answer 3

//表格的最高薪水

select salary from table order by salary desc limit 0,1

//第二高薪

select salary from table order by salary desc limit 1,1

使用此查询,您可以从表中获得第n个薪水....