Dup*_*ond 5 python legend networkx
我有以下代码来绘制带有节点的图形,但我没有添加适当的图例:(抱歉,我无法发布图像,看来我没有足够的声誉)
我想要一个有 4 种颜色的图例,例如“浅蓝色 = 过时,红色 = 草稿,黄色 = 实装,深蓝色 = init”。
我看过一些带有“分散”的解决方案,但我认为它太复杂了。有没有办法做到这一点plt.legend(G.nodes)?
这是代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("Obsolete")
G.add_node("Draft")
G.add_node("Release")
G.add_node("Initialisation")
val_map = {'kind1': 2,'kind2': 2,'Obsolete': 2,'Initialisation': 1,'Draft': 4,'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
nodes = nx.draw(G, cmap = plt.get_cmap('jet'), node_color = values)
plt.legend(G.nodes())
plt.show()
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小智 6
您在使用时似乎存在某种错误nx.draw。尝试使用nx.draw_networkx。然后matplotlib在绘制图形时使用轴 from传递它。在 (0,0) 中绘制点时,此轴应包含节点的标签和颜色 --> 这是棘手的部分。
希望能帮助到你!这是我运行的代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
# For color mapping
import matplotlib.colors as colors
import matplotlib.cm as cmx
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("Obsolete")
G.add_node("Draft")
G.add_node("Release")
G.add_node("Initialisation")
# You were missing the position.
pos=nx.spring_layout(G)
val_map = {'kind1': 2,
'kind2': 2,
'Obsolete': 2,
'Initialisation': 1,
'Draft': 4,
'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
# Color mapping
jet = cm = plt.get_cmap('jet')
cNorm = colors.Normalize(vmin=0, vmax=max(values))
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=jet)
# Using a figure to use it as a parameter when calling nx.draw_networkx
f = plt.figure(1)
ax = f.add_subplot(1,1,1)
for label in val_map:
ax.plot([0],[0],
color=scalarMap.to_rgba(val_map[label]),
label=label)
# Just fixed the color map
nx.draw_networkx(G,pos, cmap=jet, vmin=0, vmax=max(values),
node_color=values,
with_labels=False, ax=ax)
# Here is were I get an error with your code
#nodes = nx.draw(G, cmap=plt.get_cmap('jet'), node_color=values)
# Setting it to how it was looking before.
plt.axis('off')
f.set_facecolor('w')
plt.legend(loc='center')
f.tight_layout()
plt.show()
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一些有用的来源:
非常感谢您的帮助,但这不是我想要的。我做了一些更改,所以我可以让颜色图例的名称与节点的名称不同。
这是最终的代码:
import networkx as nx
import matplotlib.pyplot as plt
import numpy as np
# For color mapping
import matplotlib.colors as colors
import matplotlib.cm as cmx
G=nx.Graph()
G.add_node("kind1")
G.add_node("kind2")
G.add_node("kind3")
G.add_node("kind4")
G.add_node("kind5")
G.add_node("kind6")
# You were missing the position.
pos=nx.spring_layout(G)
val_map = {'kind1': 2,'kind2': 2,'kind3': 2,'kind4': 1,'kind5':4,'kind6': 3}
#I had this list for the name corresponding t the color but different from the node name
ColorLegend = {'Obsolete': 2,'Initialisation': 1,'Draft': 4,'Release': 3}
values = [val_map.get(node, 0) for node in G.nodes()]
# Color mapping
jet = cm = plt.get_cmap('jet')
cNorm = colors.Normalize(vmin=0, vmax=max(values))
scalarMap = cmx.ScalarMappable(norm=cNorm, cmap=jet)
# Using a figure to use it as a parameter when calling nx.draw_networkx
f = plt.figure(1)
ax = f.add_subplot(1,1,1)
for label in ColorLegend:
ax.plot([0],[0],color=scalarMap.to_rgba(ColorLegend[label]),label=label)
# Just fixed the color map
nx.draw_networkx(G,pos, cmap = jet, vmin=0, vmax= max(values),node_color=values,with_labels=True,ax=ax)
# Setting it to how it was looking before.
plt.axis('off')
f.set_facecolor('w')
plt.legend()
f.tight_layout()
plt.show()
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