Mic*_*ell 4 python django return
我已经看过这里的文档和几个类似的堆栈溢出帖子,但保存表单后我仍然无法返回该新模型的 ID/PK。它一直告诉我'ProposalForm' object has no attribute 'id'
如何在保存后立即返回ID?
这是视图:
def proposal_create_view2(request):
if request.method == 'POST':
form = ProposalForm(data=request.POST)
if form.is_valid():
form.save()
response = {}
response['proposalID'] = form.id
return response
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my_saved_model = my_model_form.save()
打印 my_saved_model.pk
编辑:
def proposal_create_view2(request):
if request.method == 'POST':
form = ProposalForm(data=request.POST)
if form.is_valid():
mysaved_model = form.save()
response = {}
response['proposalID'] = mysaved_model.id #or .pk
return render(request , 'my_template_file.html' , response)
#return response statement is NOT valid as you need to return an HttpResponse not a dict
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