use*_*480 4 c# asp.net-mvc asp.net-identity
我试图了解新的asp.net身份2.0是如何工作的,但是由于文档很少,我遇到了很多绊脚石.
我在下面的代码基于我读过的几个教程:
public class CustomRole : IdentityRole<string, CustomUserRole>
{
public CustomRole() { }
public CustomRole(string name) { Name = name; }
}
public class CustomUserRole : IdentityUserRole<string> { }
public class CustomUserClaim : IdentityUserClaim<string> { }
public class CustomUserLogin : IdentityUserLogin<string> { }
// define the application user
public class ApplicationUser : IdentityUser<string, CustomUserLogin, CustomUserRole,
CustomUserClaim>
{
[Required]
public bool IsActive { get; set; }
public async Task<ClaimsIdentity> GenerateUserIdentityAsync(UserManager<ApplicationUser> manager)
{
// Note the authenticationType must match the one defined in CookieAuthenticationOptions.AuthenticationType
var userIdentity = await manager.CreateIdentityAsync(this, DefaultAuthenticationTypes.ApplicationCookie);
// Add custom user claims here
return userIdentity;
}
}
public partial class myDbContext : IdentityDbContext<ApplicationUser, CustomRole, string,
CustomUserLogin, CustomUserRole, CustomUserClaim>
{
static myDbContext()
{
Database.SetInitializer<myDbContext>(null);
}
public myDbContext()
: base("Name=myDbContext")
{
}
public DbSet<TestTable> TestTables { get; set; }
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
modelBuilder.Configurations.Add(new TestTableMap());
}
}
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然后我有这个代码:
// create the user manager
UserManager = new UserManager<ApplicationUser>(new UserStore<ApplicationUser, CustomRole, string, CustomUserLogin, CustomUserRole,
CustomUserClaim>(
new myDbContext()));
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我在这个语句中得到一个错误,说参数类型UserStore <-ApplicationUser,CustomRole,string,CustomUserLogin,CustomUserRole,CustomUserClaim->不能分配给参数类型IUserStore <-ApplicationUser->
我在这里错过了什么?
试试这个:
UserManager = new UserManager<ApplicationUser,string>(new UserStore<ApplicationUser, CustomRole, string, CustomUserLogin, CustomUserRole, CustomUserClaim>(new myDbContext()));
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注意我使用了不同的结构UserManager,我添加string了你在ApplicationUser主键的代码中使用的第二种类型
既然你实现自定义用户/角色/等你的方式,你需要使用UserManager的UserManager<ApplicationUser,string>整个代码在用户PK作为一个字符串类型传递.
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