每个值按COUNT排序

Question

我有一个存储ID和商店所在城市的表.

我想列出从商店最多的商店开始的所有商店.

表

ID CITY
1  NYC
2  BOS
3  BOS
4  NYC
5  NYC

我想要的输出是以下,因为我在纽约市拥有最多的商店,我希望首先列出所有纽约市的位置.

1  NYC
4  NYC
5  NYC
2  BOS
3  BOS

Answer 1

SELECT count(City), City
FROM table
GROUP BY City
ORDER BY count(City);

要么

SELECT count(City) as count, City
FROM table
GROUP BY City
ORDER BY count;

啊,对不起,我误解了你的问题.我相信Peter Langs的回答是正确的.

Answer 2

这个计算单独查询中的计数,加入它和按该计数排序(SQL-Fiddle):

SELECT c.id, c.city
FROM cities c
JOIN ( SELECT city, COUNT(*) AS cnt
       FROM cities
       GROUP BY city
     ) c2 ON ( c2.city = c.city )
ORDER BY c2.cnt DESC;

Answer 3

这个解决方案不是一个非常优秀的解决方案,所以如果你的表非常大,它将需要一些时间来执行,但它会按照你的要求进行.

 select c.city, c.id, 
      (select count(*) as cnt from city c2 
       where c2.city = c.city) as order_col
 from city c
 order by order_col desc

也就是说,对于您遇到的每个城市,您都在计算该城市在数据库中出现的次数.

免责声明:这可以满足您的要求,但我不建议将其用于行数过大的生产环境.