从laravel控制器调用私有功能

bab*_*eii 1 php laravel laravel-4

我试图将一些代码提取到控制器内的私有函数,以便稍微整理一下,但函数似乎没有运行.

路线:

Route::resource('posts', 'PostsController');
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当我获取以下网址时:

/posts?page=2&posts_per_page=3&published=0
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它忽略了页面和posts_per_page变量(即它只返回前10个未发布的结果)但是当我在index方法中有这个代码时它起作用了.

public function index()
{

    // set defaults for page number and posts per page
    $page = 1;
    $postsPerPage = 10;
    $published = 1;

    $this->getPagesAndPostsPerPage($page, $postsPerPage);

    // Get published or not
    // Not published = 0
    // Published = 1

    if ( Input::has('published') )
    {
        $published = Input::get('published');
    }

    // return paginated results
    $skip = ($page - 1) * $postsPerPage;
    $posts = Post::where('published', '=', $published)
                        ->orderBy('published_date', 'desc')
                        ->skip($skip)
                        ->take($postsPerPage)
                        ->get();

    return Response::json([
        'data' => $this->transformCollection($posts)
    ], 200);
}

// Get pages and posts per page
private function getPagesAndPostsPerPage($page, $postsPerPage)
{

    // if posts per page and page are defined
    if ( Input::has('posts_per_page') && Input::has('page') )
    {
        // get inputs
        $postsPerPage = Input::get('posts_per_page');
        $page = Input::get('page');
    }

    // else if just page is defined
    elseif ( Input::has('page') ) 
    {
        $page = Input::get('page');
    }
}
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谁能看到我做错了什么?

Ste*_*man 8

你没有从中返回任何东西 $this->getPagesAndPostsPerPage($page, $postsPerPage);

函数内定义的变量是特定于函数的,这意味着如果需要获取更新的值,则需要来回传递函数变量.要么是这样,要么使用类变量(属性),以便您可以从代码中的任何位置访问更新的值.

你的控制器:

public function index()
{
    // set defaults for page number and posts per page
    $page = 1;
    $postsPerPage = 10;
    $published = 1;

    // Get the return value:
    $pagesAndPostsPerPage = $this->getPagesAndPostsPerPage($page, $postsPerPage);
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你的getPagesandPostsPerPage()功能:

private function getPagesAndPostsPerPage($page, $postsPerPage){
    //Grab pages and posts per page here

    //Create a new array and set the values
    $pagesAndPostsPerPage = array(
        'page' =>$page,
        'postsPerPage'=>$postsPerPage,
    );
    //Return the array
    return $pagesAndPostsPerPage;
}
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如果您需要更多解释,请告诉我!我很乐意帮助你.

编辑:

忘记提及,如果您不想使用ampersand(&)运算符为函数提供返回值来修改它们,也可以将变量作为函数的引用传递.

http://php.net/manual/en/language.references.pass.php

例:

function addOne(&$number)
{
    $number++;

    // Notice no return statement
}

$number = 1;

addOne($number);

echo $number; // Returns 2
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