我有一个字符串
'request=1417935385131095&to%5B%5D=596254125&to%5B%5D=683330370&e2e=%7B%22submit_0%22%3A1394711375644%7D'
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我希望数据"&到%5B%5D = 596254125&%5B%5D = 683330370&"
即我想要596254125和683330370.
我怎样才能通过rejex获得它
我试过这个
map = re.split(r"&to%5B%5D=\d+&", request)
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这不起作用.你能告诉我我做错了吗?
当有专用函数为您解析url查询字符串时,请不要使用正则表达式:
from urlparse import parse_qs
map = parse_qs(request)
to = map['to[]']
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演示:
>>> from urlparse import parse_qs
>>> request = 'request=1417935385131095&to%5B%5D=596254125&to%5B%5D=683330370&e2e=%7B%22submit_0%22%3A1394711375644%7D'
>>> map = parse_qs(request)
>>> map['to[]']
['596254125', '683330370']
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