Dud*_*ude 1 mp3 android filter
我是Android编程的新手,所以任何人都可以帮我找到我的Android设备中的所有.mp3文件.
您应该使用MediaStore.以下是我用于类似内容的示例代码:
private static ArrayList<SongModel> LoadSongsFromCard() {
ArrayList<SongModel> songs = new ArrayList<SongModel>();
// Filter only mp3s, only those marked by the MediaStore to be music and longer than 1 minute
String selection = MediaStore.Audio.Media.IS_MUSIC + " != 0"
+ " AND " + MediaStore.Audio.Media.MIME_TYPE + "= 'audio/mpeg'"
+ " AND " + MediaStore.Audio.Media.DURATION + " > 60000";
final String[] projection = new String[] {
MediaStore.Audio.Media._ID, //0
MediaStore.Audio.Media.TITLE, //1
MediaStore.Audio.Media.ARTIST, //2
MediaStore.Audio.Media.DATA, //3
MediaStore.Audio.Media.DISPLAY_NAME
};
final String sortOrder = MediaStore.Audio.AudioColumns.TITLE
+ " COLLATE LOCALIZED ASC";
Cursor cursor = null;
try {
// the uri of the table that we want to query
Uri uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI; //getContentUriForPath("");
// query the db
cursor = _context.getContentResolver().query(uri,
projection, selection, null, sortOrder);
if (cursor != null) {
cursor.moveToFirst();
while (!cursor.isAfterLast()) {
//if (cursor.getString(3).contains("AwesomePlaylists")) {
SongModel GSC = new SongModel();
GSC.ID = cursor.getLong(0);
GSC.songTitle = cursor.getString(1);
GSC.songArtist = cursor.getString(2);
GSC.path = cursor.getString(3);
// This code assumes genre is stored in the first letter of the song file name
String genreCodeString = cursor.getString(4).substring(0, 1);
if (!genreCodeString.isEmpty()) {
try {
GSC.genre = Short.parseShort(genreCodeString);
} catch (NumberFormatException ex) {
Random r = new Random();
GSC.genre = (short) r.nextInt(4);
} finally {
songs.add(GSC);
}
}
//}
cursor.moveToNext();
}
}
} catch (Exception ex) {
} finally {
if (cursor != null) {
cursor.close();
}
}
return songs;
}
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