如何在Powershell中调用带有数组参数的函数？

Question

在名为的文件中考虑此脚本 arrays.ps1

Function CallMe
{
    param($arg1, $arg2)
    Write-Host "`$arg1 is $arg1"
    Write-Host "`$arg2 is $arg2"    
}

$args = "a","b"
CallMe $args

输出:

PS C:\Users\Moomin\Documents> .\arrays.ps1
$arg1 is a b
$arg2 is

如果我修改它,那么最后一行是

CallMe $args.Split(" ")

我得到相同的输出.如何将数组传递给函数并将数组元素拆分为参数？

UPDATE

这更接近我正在做的事情:

Function CallMe
{
    param($y, $z)
    Write-Host "`$y is $y"
    Write-Host "`$z is $z"

}

Function DoSomething
{
    param($x)
    Write-Host "This function only uses one arg: $x"
}

Function DoSomethingElse
{
    Write-Host "This function does not take any arguments"   
}


$funcCalls = (
    ("DoSomething", "c"),
    ("CallMe", ("a","b")),
    ("DoSomethingElse", '')
    )


foreach ($func in $funcCalls) {
    Write-Host "Executing function $($func[0]) with arguments `"$($func[1])`""
    & $func[0] $func[1]
}

如果我运行它,这是输出:

PS C:\Users\Moomin\Documents> .\arrays.ps1
Executing function DoSomething with arguments "c"
This function only uses one arg:
Executing function CallMe with arguments "a b"
$y is a b
$z is
Executing function DoSomethingElse with arguments ""
This function does not take any arguments

Answer 1

您可以"splat"一个数组,@将每个元素作为参数传递给函数.

$array = @('a', 'b')
CallMe @array

从您更新的示例中,最好将函数存储为ScriptBlocks而不是字符串并用于.Invoke()执行.

$funcCalls = (
    ({DoSomething @args}, "c"),
    ({CallMe @args}, ("a","b")),
    ({DoSomethingElse @args}, '')
    )

foreach ($func in $funcCalls) {
    Write-Host "Executing function {$($func[0])} with arguments `"$($func[1])`""
    $func[0].Invoke($func[1])
}

请注意,参数数组会传递给自动变量$args,该变量被splat为@args.

编辑:

如果您从无法将其存储为ScriptBlocks的源中读取函数,则可以将字符串转换为ScriptBlocks [scriptblock]::Create().

$funcCalls = (
    ('DoSomething @args', "c"),
    ('CallMe @args', ("a","b")),
    ('DoSomethingElse @args', '')
    )

foreach ($func in $funcCalls) {
    Write-Host "Executing function {$($func[0])} with arguments `"$($func[1])`""
    $script = [scriptblock]::Create($func[0])
    $script.Invoke($func[1])
}