String temp_address="nothing";
try
{
String selectQuery = "SELECT lastchapter FROM Bookdetails INTO"+temp_address+"WHERE bookpath=?";
db.execSQL(selectQuery, new String[] { fileName });
System.out.println(temp_address+" result of select Query");
}
catch(Exception e)
{
System.out.println(e+" is the error here");
}
finally
{
db.close();
}
Run Code Online (Sandbox Code Playgroud)
logcat的
android.database.sqlite.SQLiteException: near "bookpath": syntax error: , while compiling: SELECT lastchapter FROM Bookdetails INTOnothingWHERE bookpath=?
Run Code Online (Sandbox Code Playgroud)
我只想获取上述查询的结果,以便存储在lastchapter中的字符串在temp_address中可用,请帮忙
我是android sqlite数据库的新手,请帮忙
laa*_*lto 20
存在SQL语法问题,您需要使用a Cursor来检索查询结果,例如rawQuery():
String selectQuery = "SELECT lastchapter FROM Bookdetails WHERE bookpath=?";
Cursor c = db.rawQuery(selectQuery, new String[] { fileName });
if (c.moveToFirst()) {
temp_address = c.getString(c.getColumnIndex("lastchapter"));
}
c.close();
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
56331 次 |
| 最近记录: |