Java if和else语句

Question

我正在尝试用Java创建一个简单的文本冒险游戏,当我键入Quit时,它结束了游戏.但相反它会询问你是否想要执行任务,即使你输入quit,假设结束代码,我尝试使用循环来修复此错误,但不得不运气.知道我哪里错了吗？

import java.util.*;

public class TextGame {
    public static void main(String[] args) {

        //Boolean run = true;
        //while (run){

        Scanner in = new Scanner(System. in );

        System.out.println("~SPECTRE~");
        System.out.println("");
        System.out.println("Please Choose One Below");
        System.out.println("");
        System.out.println("New");
        System.out.println("Quit");
        System.out.println("");

        String option;
        System.out.print("Select one of the options here: ");
        option = in .next();

        if (option.equals("New")) {
            System.out.println("Hello adventurer! Welcome to the land of Spectre.");

            String name;
            System.out.print("What is your name adventurer? ");
            name = in .next();
            System.out.println("Hello there! " + name);
        } else if (option.equals("Quit")) {
            System.out.println("*Returns to desktop*");
        }

        String quest;
        System.out.print("Would you like to go on a quest? ");
        quest = in .next();

        if (quest.equals("Yes")) {
            System.out.println("Here is a list of quests that I would like you to do ");
            System.out.println("");
            System.out.println("1) Fight the evil troll of Port Howlham");
            System.out.println("");
            System.out.println("2) Deliver supplys to the soliders in need");
            System.out.println("");
            System.out.println("3) Find the Kings lost son");
            System.out.println("");
            System.out.println("4) Find the Gemstone of Darlingbee to defeat the evil witch of Hobbitstone");

        } else {
            option.equals("");
            System.out.println("*Please pick New Game or Quit*");
        }
    }
}

Answer 1

试试这个:

} else if (option.equalsIgnoreCase("Quit")) {
    System.exit(0);
}

或这个:

} else if (option.equalsIgnoreCase("Quit")) {
    return;
}