获得一个月的天数很容易,
NSDate *today = startDate;
NSCalendar *c = [NSCalendar currentCalendar];
NSRange days = [c rangeOfUnit:NSDayCalendarUnit
inUnit:NSMonthCalendarUnit
forDate:today];
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但是如何获得当月的工作日数(周一至周五)?
不幸的是,没有直接的方法在两个日期之间循环,你无法直接从NSDate对象获得工作日.因此,您需要添加几行才能使其正常工作.这里的关键是使用NSDateComponents.在这个例子中,我使用的是公历.默认情况下,根据Apple的文档,工作日从周日开始,即第一天(字面意思为1).请不要认为周日是零(通常会感到困惑).
它可能需要一些语法更改,因为我没有在XCode上尝试过
NSInteger count = 0;
NSInteger sunday = 1;
NSInteger saturday = 7;
// Set the incremental interval for each interaction.
NSDateComponents *oneDay = [[NSDateComponents alloc] init];
[oneDay setDay:1];
// Using a Gregorian calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *currentDate = fromDate;
// Iterate from fromDate until toDate
while ([currentDate compare:toDate] == NSOrderedAscending) {
NSDateComponents *dateComponents = [calendar components:NSWeekdayCalendarUnit fromDate:currentDate];
if (dateComponents.weekday != saturday && dateComponents.weekday != sunday) {
count++;
}
// "Increment" currentDate by one day.
currentDate = [calendar dateByAddingComponents:oneDay
toDate:currentDate
options:0];
}
NSLog(@"count = %d", count);
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