Mac*_*gan 2 java swing jbutton actionlistener
我的Actionlistener有一个小问题,当我点击按钮没有任何反应?我没有看到问题所在,所以另一双眼睛可以帮助我:)
public class GameOptions extends JPanel implements ActionListener{
public GameOptions(){
System.out.println("GameOptions Class test blabla");
easyButton().addActionListener(this);
mediumButton().addActionListener(this);
hardButton().addActionListener(this);
JPanel center = new JPanel(new GridLayout(4,1,10,10));
center.add(new JLabel("Chose Difficulty Level"));
center.add(easyButton());
center.add(mediumButton());
center.add(hardButton());
this.add(center, BorderLayout.CENTER);
this.setPreferredSize(this.getPreferredSize());
this.setFocusable(true);
this.requestFocusInWindow();
}
private JButton easyButton(){
JButton levelEasy = new JButton("Easy");
return levelEasy;
}
private JButton mediumButton(){
JButton levelMedium = new JButton("Medium");
return levelMedium;
}
private JButton hardButton(){
JButton levelHard = new JButton("Hard");
return levelHard;
}
@Override
public void actionPerformed(ActionEvent e) {
Object src = e.getSource();
if(src == easyButton()){
System.out.println("Easy");
}
else if(src == mediumButton()){
System.out.println("Medium");
}
else if(src == hardButton()){
System.out.println("Hard");
}
else{
}
}
}
Run Code Online (Sandbox Code Playgroud)
您的xxxButton()方法每次都会创建新的JButton,因此您将ActionListener添加到新创建的JButton中,然后丢弃该按钮,然后添加一个完全不同的JButton,一个没有ActionListener的JButton到GUI.
建议:创建JButtons,为它们设置变量,添加ActionListener,并将相同的按钮添加到GUI.
所以不是这样的:
easyButton().addActionListener(this); // creates one JButton
center.add(easyButton()); // creates a completey different JButton
Run Code Online (Sandbox Code Playgroud)
做这个:
JButton easyButton = easyButton();
easyButton.addActionListener(this);
center.add(easyButton);
Run Code Online (Sandbox Code Playgroud)
注意,如果这是我的代码,我不确定我是否会使用JButtons.相反,也许我会使用JRadioButtons或JComboBox.
| 归档时间: |
|
| 查看次数: |
522 次 |
| 最近记录: |