如何在postgresql中找到授予用户的权限

Question

我正在使用redshift cluster db.

版:

PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.735

我只需要删除一个用户.它给出了以下错误消息:

redshiftpocdb=# drop user test_55;
ERROR:  user "test_55" cannot be dropped because the user has a privilege on some object

我是pasing\dp输出:

redshiftpocdb=# \dp
              Access privileges
 schema |  name   | type  | access privileges
--------+---------+-------+-------------------
 public | company | table |
 public | test2   | table |
 public | test22  | table |
 public | test222 | table |
 public | v_date  | table |
(5 rows)

在物理postgresql环境中,我们有一个命令DROP OWNED BY.但是这个命令在redshift中不起作用.

那么,进一步如何找出授予TEST_55的私有权？是否有任何查询来查询它(对于Oracle中的e..g,我们有DBA_ROLE_PRIVS,DBA_TAB_PRIVS ... DBA_SYS_PRIVS .etc)

谢谢

Answer 1

为了能够删除用户,您必须(至少)

• 如果他们拥有任何对象,请将所有者更改为其他用户
• 从任何对象中删除授权
• 从组中删除它们
• 从模式中删除授权

您可以使用它来查找他们拥有的任何表(然后运行"alter table owner to"):

select * from pg_tables where tableowner = 'test_55'

您可以使用它来构建脚本以撤消任何授权:

select relacl , 
'revoke ' || substring(
            case when charindex('r',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',select ' else '' end 
          ||case when charindex('w',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',update ' else '' end 
          ||case when charindex('a',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',insert ' else '' end 
          ||case when charindex('d',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',delete ' else '' end 
          ||case when charindex('R',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',rule ' else '' end 
          ||case when charindex('x',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',references ' else '' end 
          ||case when charindex('t',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',trigger ' else '' end 
          ||case when charindex('X',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',execute ' else '' end 
          ||case when charindex('U',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',usage ' else '' end 
          ||case when charindex('C',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',create ' else '' end 
          ||case when charindex('T',split_part(split_part(array_to_string(relacl, '|'),pu.usename,2 ) ,'/',1)) > 0 then ',temporary ' else '' end 
       , 2,10000)
|| ' on '||namespace||'.'||item ||' from "'||pu.usename||'";' as grantsql
from 
(SELECT 
 use.usename as subject, 
 nsp.nspname as namespace, 
 c.relname as item, 
 c.relkind as type, 
 use2.usename as owner, 
 c.relacl 
 FROM 
 pg_user use 
 cross join pg_class c 
 left join pg_namespace nsp on (c.relnamespace = nsp.oid) 
 left join pg_user use2 on (c.relowner = use2.usesysid)
 WHERE 
 c.relowner = use.usesysid  
 and  nsp.nspname NOT IN ('pg_catalog', 'pg_toast', 'information_schema')
 ORDER BY   subject,   namespace,   item 
) join pg_user pu on array_to_string(relacl, '|') like '%'||pu.usename||'%' 
where relacl is not null
 and pu.usename='test_55'

您可以使用此查询的变体来查看用户是否属于任何组(然后使用"alter group drop user"):

select usesysid, usename, nvl(groname,'default') from pg_user u 
left join pg_group g on ','||array_to_string(grolist,',')||','
  like '%,'||cast(usesysid as varchar(10))||',%' 
where usename='test_55' order by 2,1;

您可以使用此查询来查看它们是否具有任何架构授予:

select * from pg_namespace where nspowner > 1 and array_to_string(nspacl,',') like '%test_55%';