花了太长时间编码,现在我无法获得最简单的脚本

Mar*_*ark 1 javascript

有人请指出为什么这个脚本不起作用.它起初是一个AJAX脚本,我一行一行地走了,直到我留下了一个包含警报的功能,它仍然无法在IE中运行.所以请有人让我摆脱痛苦.

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<meta http-equiv="Expires" content="Fri, Jan 01 1900 00:00:00 GMT">
<meta http-equiv="Pragma" content="no-cache">
<meta http-equiv="Cache-Control" content="no-cache">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta http-equiv="Lang" content="en">
<meta name="author" content="">
<meta http-equiv="Reply-to" content="@.com">
<meta name="generator" content="PhpED 5.6">
<meta name="description" content="">
<meta name="keywords" content="">
<meta name="creation-date" content="11/11/2008">
<meta name="revisit-after" content="15 days">
<title>Untitled</title>
<link rel="stylesheet" type="text/css" href="my.css">

<script type="application/javascript">



function showUser()
{
alert('blah');
}


</script>


</head>
<body>
  <input type="button" onclick="showUser()" />
</body>
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Rol*_*man 16

尝试使用

<script type="text/javascript">
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此外,</html>缺少.


Joe*_*ssi 7

<script type="text/javascript">
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代替

<script type="application/javascript">
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