如何在Symfony 2中的类中获取Request对象？

Question

我在Symfony中有一个实现接口的类.我需要有$ para请求POST params.这是我的功能:

class WebserviceUserProvider implements UserProviderInterface
{
    public function loadUserByUsername($username)
    {
        $salt = "";
        $roles = "";
        // make a call to your webservice here

        .....
    }
...
}

我不能这样做:

public function loadUserByUsername($username, Request $request)

因为我需要实现接口,我得到这个错误:

FatalErrorException:编译错误:Actas\Gestion\UserBundle\Security\User\WebserviceUserProvider :: loadUserByUsername()声明必须与Symfony\Component\Security\Core\User\UserProviderInterface :: loadUserByUsername($ username)兼容

我如何获得请求参数？这个类是从登录调用的,我需要它发送的密码才能使用WebService来验证用户.

非常感谢你提前!

这是我在Bundle中的services.xml:

# src/Actas/Gestion/UserBundle/Resources/config/services.yml
parameters:
    webservice_user_provider.class: Actas\Gestion\UserBundle\Security\User\WebserviceUserProvider

services:
    webservice_user_provider:
        class: "%webservice_user_provider.class%"
        scope: container
        calls:
                - [setServiceContainer , ["@service_container"]]

Answer 1

除了Czechnology的答案,您还可以使用setter方法注入请求.在services.yml中添加:

my_service:
    class: Acme\DemoBundle\Service\WebserviceUserProvider
    scope: request
    calls:
        - [setRequest , ["@request"]]

然后像这样声明你的类:

use Symfony\Component\HttpFoundation\Request;

class WebserviceUserProvider implements UserProviderInterface {
    private $request;
    public function setRequest( Request $request ) {

        $this->request = $request;
    }
    // ...
}

如果您有范围扩大问题,您还可以尝试注入服务容器并从中获取请求.在服务中声明您的服务如下:

my_service:
class: Acme\DemoBundle\Service\WebserviceUserProvider
calls:
    - [setRequest , ["@service_container"]]

现在只需使用容器来获取请求:

use Symfony\Component\DependencyInjection\ContainerInterface;
use Symfony\Component\HttpFoundation\Request;

class WebserviceUserProvider implements UserProviderInterface {
    private $request;
    public function setRequest( ContainerInterface $container ) {

        $this->request = $container->get('request');
    }
    // ...
}

Answer 2

use Symfony\Component\HttpFoundation\RequestStack;

class NewService
{

    protected $request;

    public function setRequest(RequestStack $request_stack)
    {
        $this->request = $request_stack->getCurrentRequest();
    }

}

在配置文件中

services:

    new.service:
        class: Acme\DemoBundle\NewService
        calls:
            - [setRequest, [@request_stack]]

参考:http: //symfony.com/blog/new-in-symfony-2-4-the-request-stack