static class Program
{
static void Main(string carMake, string carModel, string carColour, string bikeModel, string bikeMake, string bikeColour, string truckMake, string truckModel, string truckColour)
{
car Mynewcar = new car();
motorbike Mynewbike = new motorbike();
truck Mynewtruck = new truck();
int choice = 0;
while (choice != 5)
{
Console.WriteLine("MENU");
Console.WriteLine("What service do you need");
Console.WriteLine("1. Car");
Console.WriteLine("2. Motorbike");
Console.WriteLine("3. Truck");
Console.WriteLine("4. Search");
Console.WriteLine("5. Exit");
choice = int.Parse(Console.ReadLine());
switch (choice)
{
case 1:
Console.WriteLine("What is the car make?");
Mynewcar.make = Console.ReadLine().ToLower();
carMake = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("What is the car model?");
Mynewcar.model = Console.ReadLine().ToLower();
carModel = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("What is the car Colour?");
Mynewcar.colour = Console.ReadLine().ToLower();
carColour = Console.ReadLine();
Console.WriteLine("");
break;
case 2:
Console.WriteLine("what is the motorbike make");
Mynewbike.make = Console.ReadLine().ToLower();
bikeMake = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("what is the motorbike model");
Mynewbike.model = Console.ReadLine().ToLower();
bikeModel = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("what is the motorbike colour");
Mynewbike.colour = Console.ReadLine().ToLower();
bikeColour = Console.ReadLine();
Console.WriteLine("");
break;
case 3:
Console.WriteLine("what is the trucks make");
Mynewtruck.make = Console.ReadLine().ToLower();
truckMake = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("what is the trucks model");
Mynewtruck.model = Console.ReadLine().ToLower();
truckModel = Console.ReadLine();
Console.WriteLine("");
Console.WriteLine("what is the trucks colour");
Mynewtruck.colour = Console.ReadLine().ToLower();
truckColour = Console.ReadLine();
Console.WriteLine("");
break;
case 4:
string searchchoice = "";
Console.WriteLine("select Car, Motobike or truck to search?");
searchchoice = Console.ReadLine().ToLower();
if (searchchoice.Equals("car"))
{
Console.WriteLine("Car in inventory: {0} - {1} - {2}", carMake, carModel, carColour);
}
else if (searchchoice.Equals("motorbike"))
{
Console.WriteLine("Motorbike in inventory: {0} - {1} - {2}", bikeMake, bikeModel, bikeColour);
}
else
{
Console.WriteLine("Trucks in inventory: {0} - {1} - {2}", truckMake, truckModel, truckColour);
}
Console.ReadLine();
break;
case 5:
break;
default:
Console.WriteLine("Sorry, invalid selection");
break;
}
}
}
class car
{
public string make { get; set; }
public string model { get; set; }
public string colour { get; set; }
public List<String> carList(car Mynewcar)
{
List<String> caradd = new List<String>();
caradd.Add(Mynewcar.make);
string carMake = Mynewcar.make;
caradd.Add(Mynewcar.model);
string carModel = Mynewcar.model;
caradd.Add(Mynewcar.colour);
string carColour = Mynewcar.model;
return caradd;
}
}
class motorbike : car
{
public List<String> bikeList(motorbike Mynewbike)
{
List<String> bikeadd = new List<String>();
bikeadd.Add(Mynewbike.model);
string bikeModel = Mynewbike.model;
bikeadd.Add(Mynewbike.make);
string bikeMake = Mynewbike.make;
bikeadd.Add(Mynewbike.colour);
string bikeColour = Mynewbike.colour;
return bikeadd;
}
}
class truck : car
{
public List<String> truckList(truck Mynewtruck)
{
List<String> truckadd = new List<String>();
truckadd.Add(Mynewtruck.make);
string truckMake = Mynewtruck.make;
truckadd.Add(Mynewtruck.model);
string truckModel = Mynewtruck.model;
truckadd.Add(Mynewtruck.colour);
string truckColour = Mynewtruck.colour;
return truckadd;
}
}
}
我只是想知道是否有人可以查看我的代码,看看我可以改进哪些方面.
此外,我正在努力为汽车,自行车和卡车的列表中添加多个项目.你会怎么做,这样你可以添加属性的多个实例并将它们列出到控制台？
Mal*_*ick 20
感谢AddRange:
例:
public class Person
{
private string Name;
private string FirstName;
public Person(string name, string firstname) => (Name, FirstName) = (name, firstname);
}
要添加多个Person到List<>:
List<Person> listofPersons = new List<Person>();
listofPersons.AddRange(new List<Person>
{
new Person("John1", "Doe" ),
new Person("John2", "Doe" ),
new Person("John3", "Doe" ),
});
Jer*_*vel 14
代码检查:
这是offtopic,但是CodeReview的人们非常乐意为您提供帮助.
我强烈建议你这样做,你的代码中有几件需要注意的事情.同样地,我建议你开始阅读教程,因为没有充分的理由不这样做.
列表:
正如你自己说的:你需要一个项目清单.它现在的方式只存储对一个项目的引用.幸运的是,有一组相关的对象:a List.
列表非常简单易用,但无论如何都要查看相关文档.
在列表中保留多个自行车的一个非常简单的示例:
List<Motorbike> bikes = new List<Motorbike>();
bikes.add(new Bike { make = "Honda", color = "brown" });
bikes.add(new Bike { make = "Vroom", color = "red" });
要迭代列表,您可以使用以下foreach语句:
foreach(var bike in bikes) {
Console.WriteLine(bike.make);
}
在使用扩展方法、泛型和params关键字的现代 C# 中，您可以在 List 类上创建泛型方法，该方法允许您将无限数量的项目添加到包含任何类型的列表中：
static class ListExtensions
{
static public void Add<T>(this List<T> list, params T[] additions)
{
foreach(T addition in additions)
{
list.Add(addition)
}
}
}
使用字符串列表和整数列表的示例用法：
var stringList = new List<string>();
stringList.Add("Hello", "World", "!");
var intList = new List<int>();
intList.Add(1, 2, 3, 4, 5);
小智 6
另一种有用的方法是使用Concat。
更多信息请参见官方文档。
List<string> first = new List<string> { "One", "Two", "Three" };
List<string> second = new List<string>() { "Four", "Five" };
first.Concat(second);
输出将是。
One
Two
Three
Four
Five
还有另一个类似的答案。