Django模型查询使用join

Mit*_*ril 5 python django django-orm django-queryset

我想使查询工作如下sql:

sql_str = '''
    select * from luckydraw_winner W
    inner join luckydraw_prizeverificationcodesmslog L on W.id =L.winner_id
    where W.lucky_draw_id = %s
    limit 10
'''
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楷模:

class Winner(models.Model):
    lucky_draw = models.ForeignKey(LuckyDraw)
    participation = models.ForeignKey(Participation)
    prize = models.ForeignKey(Prize)
    mobile_number = models.CharField(max_length=15, null=True, default = None)

class PrizeVerificationCodeSMSLog(models.Model):
    winner = models.ForeignKey(Winner)
    mobile_number = models.CharField(max_length=15, db_index=True)
    created_on = models.DateTimeField(auto_now_add=True)
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因为 mobile_number并不总是填写Winner模型,我想要的是拥有手机号码或获得短信的赢家.所以必须加入PrizeVerificationCodeSMSLog以实现我的目的.
只有赢家很简单:

winners = models.Winner.objects.filter(lucky_draw_id=id).order_by('-created_on')[:10]
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但我不知道可以添加什么过滤器来加入PrizeVerificationCodeSMSLog.


我终于明白了如何在django中检索我想要的数据.

如果您想让A另一个B具有外键的模型限制模型A,请不要尝试使用filter().因为A不知道B,但B知道A!只是检索A基地B.

fra*_*les 4

尝试

logs = PrizeVerificationCodeSMSLog.objects.filter(winner__lucky_draw_id=id).order_by('-created_on')
winners = logs.select_related("winner")[:10]
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这会生成以下查询

SELECT "prizeverificationcodesmslog"."id", "prizeverificationcodesmslog"."winner_id", 
    "prizeverificationcodesmslog"."mobile_number", "prizeverificationcodesmslog"."created_on", 
    "winner"."id", "winner"."lucky_draw_id", "winner"."participation_id", 
    "winner"."prize_id", "winner"."mobile_number" 
FROM "prizeverificationcodesmslog" 
INNER JOIN "winner" ON ("prizeverificationcodesmslog"."winner_id" = "winner"."id") 
WHERE "winner"."lucky_draw_id" = 1  
ORDER BY "prizeverificationcodesmslog"."created_on" 
DESC LIMIT 10;
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我不确定您的要求是什么,但您可能想通过 Max PrizeVerificationCodeSMSLog 进行聚合

请参阅https://docs.djangoproject.com/en/1.5/topics/db/aggregation/