是否有可能为循环2列表与另一个大小最小的"重新循环"?
例:
list = [1,2,3,4,5,6,7,8,10]
list2 = [a,b]
newlist = []
for number, letter in zip(list, list2):
newlist.append(item)
newlist.append(item2)
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循环停在[1a,2b]因为list2中没有其他项目,list2是否可以重新开始直到list1为空?即:newlist = [1a,2b,3a,4b,5a,6b]等?
thkx!
>>> l1 = [1,2,3,4,5,6,7,8,10]
>>> l2 = ['a','b']
>>>
>>> from itertools import cycle
>>>
>>> for number, letter in zip(l1, cycle(l2)):
... print number, letter
...
1 a
2 b
3 a
4 b
5 a
6 b
7 a
8 b
10 a
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另外,您不应该将其list用作变量名,因为该名称已由内置函数使用list().