插入查询后更新状态

Question

$stmt = "insert into {CI}payment_logs (customer_id, invoice_id, invoice_total_amount, invoice_paid_amount, customer_paid_amount, invoice_payment_on ) "
                . "values( ?, ?, ?, ?, ?, NOW() )";
$this->db->query( $stmt, array( $Customer_Id, $Invoice_Id, $Invoice_Total_Amount, $Deducted_Amount, $Paid_By_Cust ) );        
$Log_Id = $this->db->insert_id(); // Returns Last Insert ID

根据我的需要,这是正常工作,但我必须在特定条件下更新同一个表中每一行的状态.看看图片,

这是上述查询的插入数据.如您所见,invoice_total_amount是总金额,但这个金额在第三行数据中完成.我必须更新该invoice_status字段,因为paid在高度点亮量SUM等于invoice_total_amount和之后,我必须将状态更新为partial.我尝试更新状态以添加触发器但不成功.

然后我尝试使用此命令的PHP.

update {CI}payment_logs 
    set invoice_status = IF( invoice_total_amount = sum(invoices_paid_amount), 'paid', 'partial' ) 
where log_id = ?

但我没有得到invoices_paid_amountinvoice_id = 的SUM 5,我尝试在IF条件下使用子查询,但它无效我的查询.

请帮我解决单查询或触发解决方案..

Answer 1

连接计算总和的子查询。

UPDATE {CI}payment_logs l1
JOIN (SELECT invoice_id, SUM(invoices_paid_amount) total
      FROM {CI}payment_logs
      GROUP BY invoice_id) l2
ON l1.invoice_id = l2.invoice_id
SET invoice_status = IF(invoice_total_amount = total, 'paid', 'partial')
WHERE log_id = ?