ios - 介于日期之间(实际日期,而不是天数)

Question

我有两个日期字符串,我希望在日期之间得到.例如,

NSString *startDate = @"25-01-2014";
NSString *endDate = @"02-02-2014";

在两个日期之间(26-01-2014,27-01-2014,28-01-2014 .......)最好包括startDate和endDate.我设法找到的大多数问题都要求天数.但我需要它才能成为实际日期.无论如何,我可以在日期之间进入吗？

NSString *start = @"2010-09-01";
NSString *end = @"2010-12-05";

NSDateFormatter *f = [[NSDateFormatter alloc] init];
[f setDateFormat:@"yyyy-MM-dd"];
NSDate *startDate = [f dateFromString:start];
NSDate *endDate = [f dateFromString:end];

NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorianCalendar components:NSDayCalendarUnit
                                                    fromDate:startDate
                                                      toDate:endDate
                                                     options:0];

NSLog(@"Difference in date components: %d", components.day);

我设法找到这只返回天数差异.

Answer 1

NSString *start = @"2010-09-01";
NSString *end = @"2010-12-05";

NSDateFormatter *f = [[NSDateFormatter alloc] init];
[f setDateFormat:@"yyyy-MM-dd"];
NSDate *startDate = [f dateFromString:start];
NSDate *endDate = [f dateFromString:end];

NSMutableArray *dates = [@[startDate] mutableCopy];


NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorianCalendar components:NSDayCalendarUnit
                                                    fromDate:startDate
                                                      toDate:endDate
                                                     options:0];

for (int i = 1; i < components.day; ++i) {
    NSDateComponents *newComponents = [NSDateComponents new];
    newComponents.day = i;

    NSDate *date = [gregorianCalendar dateByAddingComponents:newComponents 
                                                      toDate:startDate 
                                                     options:0];
    [dates addObject:date];
}

[dates addObject:endDate];

数组dates现在包含之间的日期列表startDate和endDate包括那些午夜在设备的时区.
请注意,在某些时区上,这可能会导致问题,因为此时可能会发生与夏令时的切换,请参阅WWDC 2011视频"会话117 - 执行日历计算"以获取更多信息.一个技巧是将小时转移到保存时间,即中午,进行计算,然后减去12小时.