isalpha python函数不会考虑空格

Question

所以下面的代码接受输入并确保输入由字母而不是数字组成.如果输入包含空格,我将如何使它也打印原始

original = raw_input("Type the name of the application: ")

if original.isalpha() and len(original) > 0:
    print original
else:
    print "empty"

尝试了这段代码,但是当输入数字也是如此.

original = raw_input("Type the word you want to change: ")

if original.isalpha() or len(original) > 0:
    print original
else:
    print "empty"

Answer 1

看起来这就是字符串的工作方式.

两种选择:

if all(x.isalpha() or x.isspace() for x in original):

(根据检查员G4dget的建议修改如下)

要么

original.replace(' ','').isalpha()

应该管用.