PHP OOP无法设置私有属性

Question

我有一个扩展用户的UserFavorite类.当我使用类构造函数创建新对象时,setters无法设置属性.

构造函数:

public function __construct($username, $tabId, $favName, $favUrl = null, $favPosition = null, $favComment = null) {
    parent::__construct($username);
    $this->tabId = $this->setTabId($tabId);
    $this->favName = $this->setFavName($favName);
    $this->favUrl = $this->setFavUrl($favUrl);
    $this->favPosition = $this->setFavPosition($favPosition);
    if ($favComment) {
        $this->favComment = $this->setFavComment($favComment); 
    }
}

二传手:

public function setFavUrl($favUrl) {
        $url = filter_var($favUrl, FILTER_VALIDATE_URL);
        if (!$url) {
            echo $this->showError(...);
            exit;
        }
        echo $url; // THIS LOGS THE URL
        $this->favUrl = $url;
    }

我创造了新的实例 $fav = new UserFavorite($user->getUsername(), 1, 'favorite', 'http://abv.bg', 5, 'mamatisiebalo' );

当我打印$fav我收到:

favorite<pre>UserFavorite Object
(
    [favName:UserFavorite:private] => 
    [tabId:UserFavorite:private] => 
    [favUrl:UserFavorite:private] => 
    [favPosition:UserFavorite:private] => 
    [favComment:UserFavorite:private] => 
    [_favId:UserFavorite:private] => 
    [username:protected] => myUserName
    [_userId:protected] => 1
)

有任何想法吗？

Answer 1

您正在设置$this->favUrlsetter函数,然后通过将setter函数的结果分配给同一个变量来覆盖它.

如果你改变了

$this->favUrl = $this->setFavUrl($favUrl);

至

$this->setFavUrl($favUrl);

你应该没事.