C#Serialization to file,覆盖如果存在

Question

我有以下方法(如下所示),因为您可以看到它将对象序列化为XML文件.我遇到的主要问题是我想让函数覆盖文件(如果存在).我知道如果它确实存在,我可以先删除该文件,但这也意味着我可能会在我的应用程序中引发一些错误.所以我想要一个全有或全无,覆盖方法......

这是函数,关于如何实现这一点的任何想法？

/// <summary>
    /// Serializes an object to an xml file.
    /// </summary>
    /// <param name="obj">
    /// The object to serialize.
    /// </param>
    /// <param name="type">
    /// The class type of the object being passed.
    /// </param>
    /// <param name="fileName">
    /// The filename where the object should be saved to.
    /// </param>
    /// <param name="xsltPath">
    /// Pass a null if not required.
    /// </param>
    public static void SerializeToXmlFile(object obj, Type type, string fileName, string xsltPath )
    {
        var ns = new XmlSerializerNamespaces();
        ns.Add(String.Empty, String.Empty);
        var serializer = new XmlSerializer(type);

        var settings = new XmlWriterSettings {Indent = true, IndentChars = "\t"};


        using (var w = XmlWriter.Create(fileName,settings))
        {

            if (!String.IsNullOrEmpty(xsltPath))
            {
                w.WriteProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"" + xsltPath + "\"");

            }
            serializer.Serialize(w, obj, ns);
        }
    }

Answer 1

使用XmlWriter.Create带有Stream而不是字符串的重载版本,并使用File.Create创建/覆盖文件:

using (var w = XmlWriter.Create(File.Create(fileName), settings))
...