使用C am我认为以多个零开头的文字被认为是八进制的吗？

Question

在下面的C代码中是用于所有这些定义的八进制文字？即使他们从多个零开始？

#define TCL_REG_BASIC       000000  /* BREs (convenience). */
#define TCL_REG_EXTENDED    000001  /* EREs. */
#define TCL_REG_ADVF        000002  /* Advanced features in EREs. */
#define TCL_REG_ADVANCED    000003  /* AREs (which are also EREs). */
#define TCL_REG_QUOTE       000004  /* No special characters, none. */
#define TCL_REG_NOCASE      000010  /* Ignore case. */
#define TCL_REG_NOSUB       000020  /* Don't care about subexpressions. */
#define TCL_REG_EXPANDED    000040  /* Expanded format, white space & comments. */
#define TCL_REG_NLSTOP      000100  /* \n doesn't match . or [^ ] */
#define TCL_REG_NLANCH      000200  /* ^ matches after \n, $ before. */
#define TCL_REG_NEWLINE     000300  /* Newlines are line terminators. */
#define TCL_REG_CANMATCH    001000  /* Report details on partial/limited * matches. */

Answer 1

从C标准,6.4.4.1第3段:

八进制常量由pre fi x 0组成,可选地后跟一个数字0到7的序列