Sti*_*ube 5 mysql sql join group-by aggregate-functions
我有两个表格,包括以下字段
emp_table: emp_id, emp_name
salary_increase: emp_id, inc_date, inc_amount
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我需要写一个查询,该查询给出了员工的详细信息,员工获得加薪的次数,最大增加金额的值以及增加的日期.这是我到目前为止:
SELECT e.*, count(i.inc_amount), max(i.inc_amount)
FROM salary_increase AS i
RIGHT JOIN emp_table AS e
ON i.emp_id=e.emp_id
GROUP BY e.emp_id;
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这正确地给出了除了授予最大增加的日期之外的所有要求.我试过以下但没有成功:
SELECT e.*, count(i.inc_amount), max(inc_amount), t.inc_date
FROM salary_increase AS i
RIGHT JOIN emp_table AS e
ON i.emp_id=e.emp_id
RIGHT JOIN
(
SELECT emp_id, inc_date FROM salary_increase
WHERE inc_amount=max(inc_amount) GROUP BY emp_id
) AS t
ON e.emp_id=t.emp_id
GROUP BY e.emp_id;
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这会给出错误"组功能的无效使用".有谁知道我做错了什么?
您不能WHERE inc_amount=max(inc_amount)在where子句中执行此操作,无论是使用HAVING还是在连接条件下执行此操作,请尝试以下操作:
SELECT
e.emp_id,
e.inc_date,
t.TotalInc,
t.MaxIncAmount
FROM salary_increase AS i
INNER JOIN emp_table AS e ON i.emp_id=e.emp_id
INNER JOIN
(
SELECT
emp_id,
MAX(inc_amount) AS MaxIncAmount,
COUNT(i.inc_amount) AS TotalInc
FROM salary_increase
GROUP BY emp_id
) AS t ON e.emp_id = t.emp_id AND e.inc_amount = t.MaxIncAmount;
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