您的SQL语法有错误; 查看与您的MySQL服务器版本对应的手册,以便在附近使用正确的语法

Question

您的SQL语法有错误; 检查与MySQL服务器版本对应的手册,以便在第1行的'where LastName = Iguin'附近使用正确的语法

我无法修复错误:(有人可以帮助我

这是我的代码

try
{
    string contactNumVal = txtColContact.Text;

    if (contactNumVal.Length < 11)
    {
        MessageBox.Show("The Contact Number must have 11 digit");
    }
    else
    {
        DialogResult dw;

        dw = MessageBox.Show("Are you sure you want to Edit this data", "Confirm Deletion", MessageBoxButtons.YesNo);
        if (dw == DialogResult.Yes)
        {
            string MyConString = "SERVER=localhost;" +
                     "DATABASE=prototype_db;" +
                     "UID=root;";
            using (MySqlConnection connection = new MySqlConnection(MyConString))
            {
                connection.Open();
                DataTable dt = new DataTable();
                using (MySqlDataAdapter da = new MySqlDataAdapter("Select Collector_ID, LastName, " +
                              "FirstName,MiddleName,Address,ContactNo,BirtDay,Gender" +
                              "from collector_profile where LastName like @clname", connection))
                {
                    da.SelectCommand.Parameters.AddWithValue("@clname", "%" + txtColLname.Text + "%");

                    da.Fill(dt);

                    dt.Rows[0].BeginEdit();

                    dt.Rows[0][1] = txtColLname.Text;
                    dt.Rows[0][2] = txtColFname.Text;
                    dt.Rows[0][3] = txtColMname.Text;
                    dt.Rows[0][4] = txtColAddress.Text;
                    dt.Rows[0][5] = txtColContact.Text;
                    dt.Rows[0][6] = dtpCbday.ToString();
                    dt.Rows[0][7] = cmbCgender.SelectedItem.ToString();

                    dt.Rows[0].EndEdit();
                    MySqlCommandBuilder cb = new MySqlCommandBuilder(da);
                    da.Update(dt);

                    connection.Close();
                }
            }

            MessageBox.Show("Data is now updated");
        }

    }
}

catch (Exception error)
{
    MessageBox.Show(error.ToString());
}

Answer 1

您需要在SQL字符串之间Gender和之间from留出空格.

  using (MySqlDataAdapter da = 
           new MySqlDataAdapter("Select Collector_ID, LastName, " +
           "FirstName,MiddleName,Address,ContactNo,BirtDay,Gender " + //here
           "from collector_profile where LastName like @clname", connection))

对于将来的调试,请尝试从debug中复制SQL命令文本,然后在SQL Server中执行相同的操作以查看它是否有效.(这会让你更好地了解错误)