相同字节显示不同的结果

Question

在不更改byte [] numArray的情况下,即使字节保持完全相同,两个消息框也会显示不同的输出.我糊涂了.

第一个MessageBox的结果:stream:stream to =""version ="1.0"xmlns:stream ="http://etherx.jabber.org/streams">

第二个MessageBox的结果: F^ v

第三个MessageBox:"匹配"

MessageBox.Show(System.Text.Encoding.UTF8.GetString(numArray));
byte[] num1 = numArray;
byte[] encrypted =  getEncryptedInit(numArray);
MessageBox.Show(System.Text.Encoding.UTF8.GetString(numArray));
byte[] num2 = numArray;
if (num1.SequenceEqual<byte>(num2) == true)
{
    MessageBox.Show("Match");
}

Answer 1

getEncryptedInit必须修改内容numArray.

既然num1和num2都指向numArray,当然它们是等价的.

请记住,数组是引用类型,所以当你说num1 = numArray,你只是将num1变量指向内存中numArray指向的相同位置.如果你真的想捕捉numArray特定时间点的样子,你必须复制它,而不是仅仅做一个简单的任务.

请考虑以下示例:

void DoStuff(byte[] bytes) {
  for (int i = 0; i < bytes.Length; i++) {
    bytes[i] = 42;
  }
}

bool Main() {
  // This allocates some space in memory, and stores 1,2,3,4 there.
  byte[] numArray = new byte[] { 1, 2, 3, 4 };

  // This points to the same space in memory allocated above.
  byte[] num1 = numArray;

  // This modifies what is stored in the memory allocated above.
  DoStuff(numArray);

  // This points to the same space in memory allocated above.
  byte[] num2 = numArray;

  return (num1 == num2 == numArray); // always true
}