use*_*419 2 javascript arrays node.js
我知道还有其他页面,但我想让自己的工作,我不知道为什么它不起作用.我是node.js的新手.
for (var index in output)
{
if (opt.options.showEmpty != true)
{
var check = arrayIsEmpty(output[index]);
if ( check == true )
{
continue;
}
else
{
var array = removingEmptyString(output[index]);
console.log(index + "\t" + array);
//console.log(index+ "\t" + output[index]);
}
}
}
function removingEmptyString(array)
{
var newArray;
for( var i = 0; i < array.length; i++)
{
if(array[i] != "" || array[i] != null)
{
newArray[i] = array[i];
}
}
return newArray;
}
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我的结果是树,,,我以前在我写的代码之前得到了.现在我得到一个错误
newArray[i] = array[i];
^
TypeError: Cannot set property '0' of undefined
at removingEmptyString (librarySeeker.js:130:18)
at result (librarySeeker.js:76:19)
at /async/lib/async.js:226:13
at async/lib/async.js:113:25
at async/lib/async.js:24:16
at async/lib/async.js:223:17
at /async/lib/async.js:510:34
at IncomingMessage.<anonymous> (pull.js:295:10)
at IncomingMessage.EventEmitter.emit (events.js:117:20)
at _stream_readable.js:910:16
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你可以.filter在Array的原型中使用该方法.
var pirate = ['a','1','',0];
function arr (value) {
return value.filter(function (item) {
return item !== '';
});
}
arr(pirate);
// <- ['a','1',0]
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作为替代方案,您可能需要考虑将回调命名为 .filter
var pirate = ['a','1','',0];
function worthy (value) {
return value !== '';
}
pirate.filter(worthy);
// <- ['a','1',0]
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