SQLAlchemy查询,按关系加入关系和顺序

sun*_*nce 10 python sqlalchemy flask flask-sqlalchemy

我有两个SQLAlchemy模型设置如下:

##############
# Post Model #
##############
class Post(db.Model):
    id = db.Column(db.Integer, primary_key = True)
    title = db.Column(db.String(250))
    content = db.Column(db.String(5000))
    timestamp = db.Column(db.Integer)
    author_id = db.Column(db.Integer, db.ForeignKey('user.id'))
    likes = db.relationship('Like', backref = 'post', lazy = 'dynamic')

###############
# Likes Model #
###############
class Like(db.Model):
    id = db.Column(db.Integer, primary_key = True)
    voter_id = db.Column(db.Integer, db.ForeignKey('user.id'))
    post_id = db.Column(db.Integer, db.ForeignKey('post.id'))
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正如您所看到的,这些帖子上有帖子模型和用户喜欢的模型.我想创建一个选择所有帖子的查询,按照帖子的喜欢数量排序.在shell中,我可以运行:

SELECT post.*, 
       count(like.id) AS num_likes
FROM post
LEFT JOIN like
ON post.id = like.post_id
GROUP BY post.id;
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什么是等效的SQLAlchemy命令?

谢谢!

Mig*_*uel 11

从原始查询到Flask-SQLAlchemy的转换非常具有机械性:

db.session.query(Post, db.func.count(Like.id)).outerjoin(Like).group_by(Post.id)
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  • 谢谢,这就是我想要的!我稍微修改了它,所以我可以使用Flask-SQLAlchemy BaseQuery paginate()方法:```Post.query.outerjoin(Like).group_by(Post.id).order_by(db.func.count(Like.id). desc(),Post.timestamp.desc()).paginate(page_num,10,False)```但它或多或少相同.再次感谢! (3认同)