没有错误:没有调用PDO构造函数

use*_*124 0 php pdo

下午好.我昨天开始使用PDO,我有一些问题.我正在创建extendet类,它不起作用,我找不到bug.

这是我的助手类的代码,对于工作女巫PDO:

    class EPDO extends PDO {
  /** Some identificator of connection*/
  public $db;

  /**
   * Creating new PDO connections
   */     
  public function __construct($dbhost, $dbname, $dbuser = 'root', $dbpass = '', $dbtype = 'mysql') {
    $db = new PDO($dbtype . ':host=' . $dbhost . ';dbname=' . $dbname, $dbuser, $dbpass);
  } 

  /**
   * Insert into database with using transaction (if operation failed the changes go before)
   */     
  public function insert($statement) {
    $db->beginTransaction();

    $status = $db->exec($statement);
    if ($status) {
      $db->commit();  
    } else {
      $db->rollback();
    }
  } 
}
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这是无法使用的代码:

$stm = $db->prepare('SELECT id FROM `startups` WHERE id = :id');
$params = array(':id' => $child->id);
$ok = $stm->execute($params);
$row = $stm->fetch(PDO::FETCH_ASSOC);
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在此代码之前,我当然按以下方式调用连接:

  require_once 'EPDO.php';

  try {
    $db = new EPDO('--server--', '--database--', '--user--', '--pass--');
  }
  catch (PDOException $err) {
    echo "Chyba spojeni: " . $err->getMessage();
  }
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非常感谢,对不起我的英语.

gar*_*jie 5

问题是你正在扩展PDO类并重写构造函数,所有这些都不需要调用构造函数.

此外,每次创建新对象时,您实际上都在创建两个数据库连接.

这应该有助于解决您的问题,并减少创建的连接:

class EPDO extends PDO {
    /** Some identificator of connection*/
    public $db;

    /**
     * Creating new PDO connections
     */     
    public function __construct($dbhost, $dbname, $dbuser = 'root', $dbpass = '', $dbtype = 'mysql') {
        parent::__construct($dbtype . ':host=' . $dbhost . ';dbname=' . $dbname, $dbuser, $dbpass);
    } 

    /**
     * Insert into database with using transaction (if operation failed the changes go before)
     */     
    public function insert($statement) {
        $this->beginTransaction();
        $status = $this->exec($statement);
        if ($status) {
            $this->commit();  
        } else {
            $this->rollback();
        }
    }
}
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