如何在自己的线程中执行Web请求?

Nik*_*lin 11 java multithreading android

我正在创建一个Android应用程序,它必须在后台执行Web请求,然后处理接收的数据并根据服务器响应修改用户界面.

在后台发布请求和处理数据的目的是避免冻结用户界面.但是目前我注意到用户界面已经冻结,所以我不确定逻辑是否正常工作.

这是代码的一部分,它应该在自己的线程中发布请求和处理响应,然后将数据传递给GUI:

public class ServerConnection {

Queue<String> requests;

...

DefaultHttpClient httpClient;
HttpHost targetHost;

Handler handler;

ServerResponseHandler responseHandler;
Activity activity;

public ServerConnection(Activity activity){
    this.activity = activity;
    this.responseHandler = (ServerResponseHandler) activity;
    httpClient = new DefaultHttpClient();
    targetHost = new HttpHost(TARGET_DOMAIN, 80, "http");
    requests = new LinkedList<String>();
}



private Runnable requestSender = new Runnable(){

    @Override
    public void run() {
        if(!requests.isEmpty()){
            String requestString = requests.remove();
            HttpGet httpGet = new HttpGet(requestString);
            httpGet.addHeader("Accept", "text/xml");
            String encodingString = "testuser:testpass";
            String sEncodedString = Base64Coder.encodeString(encodingString);

            try{

                String sContent = fetchURL(requestString, sEncodedString);

                XMLParser xmlParser = new XMLParser();

                List <Product> products = xmlParser.getProducts(sContent);

                responseHandler.onProductsResponse(products);
            }
            catch(Exception ex){
                Log.e(TAG, ex.getMessage());
            }
        }
    }
};

public void sendRequest(String requestString){
    requests.add(requestString);
    handler = new Handler();
    handler.post(requestSender);
}
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方法sendRequest()是从实现ServerResponseHandler的主活动中调用的.我猜这个请求是在自己的线程中执行的并且通过调用来执行

responseHandler.onProductsResponse(产品);

产品列表(来自Web的数据)将传递给主要活动.无论如何,由于性能不佳,如果有人能够纠正上述逻辑中的任何可能问题或建议任何其他(更好)选项,我将不胜感激.

Ret*_*ier 21

我建议你看一下ASyncTask类(从Android 1.5开始提供).

它简化了创建后台线程的过程,该线程一旦完成就与GUI线程同步.

你应该能够实现你正在尝试使用代码的东西列出这个

private class DownloadFilesTask extends AsyncTask<String, List<Product>, Integer> {
     protected List<Products> doInBackground(String... requestStrings) {
        int count = requestStrings.length;
        int results = 0;
        for (int i = 0; i < count; i++) {
          String requestString = requestStrings[i];
          HttpGet httpGet = new HttpGet(requestString);
          httpGet.addHeader("Accept", "text/xml");
          String encodingString = "testuser:testpass";
          String sEncodedString = Base64Coder.encodeString(encodingString);
          try{
            String sContent = fetchURL(requestString, sEncodedString);
            XMLParser xmlParser = new XMLParser();
            List <Product> products = xmlParser.getProducts(sContent);
            results++;
            publishProgress(products);
          }
          catch(Exception ex){
            Log.e(TAG, ex.getMessage());
          }
        }
        return results;
     }

     protected void onProgressUpdate(Integer... progress) {
         // TODO You are on the GUI thread, and the first element in 
         // the progress parameter contains the last progress
         // published from doInBackground, so update your GUI
     }

     protected void onPostExecute(int result) {
       // Processing is complete, result contains the number of 
       // results you processed
     }
 }
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并通过调用执行

new DownloadFilesTask().execute(url1, url2, url3);
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  • AsyncTask是要走的路. (2认同)