使用查询将数据插入临时表

Question

我有一个输出当前数据的现有查询,我想将它插入Temp表中,但是我遇到了一些问题.有人会对如何做到这一点有所了解吗？

这是一个例子

SELECT *
FROM  (SELECT Received,
              Total,
              Answer,
              ( CASE
                  WHEN application LIKE '%STUFF%' THEN 'MORESTUFF'
                END ) AS application
       FROM   FirstTable
       WHERE  Recieved = 1
              AND application = 'MORESTUFF'
       GROUP  BY CASE
                   WHEN application LIKE '%STUFF%' THEN 'MORESTUFF'
                 END) data
WHERE  application LIKE isNull('%MORESTUFF%', '%') 

这似乎以我需要的方式输出我的数据,但我想把它传递到Temp Table.我的问题是我对SQL查询很新,但却找不到办法.或者,如果它是可能的.如果不可能,有没有更好的方法将我要查找的数据WHERE application LIKE isNull('%MORESTUFF%','%')放入临时表？

任何帮助将非常感激!谢谢!

Answer 1

SELECT *
INTO #Temp
FROM

  (SELECT
     Received,
     Total,
     Answer,
     (CASE WHEN application LIKE '%STUFF%' THEN 'MORESTUFF' END) AS application
   FROM
     FirstTable
   WHERE
     Recieved = 1 AND
     application = 'MORESTUFF'
   GROUP BY
     CASE WHEN application LIKE '%STUFF%' THEN 'MORESTUFF' END) data
WHERE
  application LIKE
    isNull(
      '%MORESTUFF%',
      '%')

Answer 2

SQL Server R2 2008需要AS如下子句:

SELECT * 
INTO #temp
FROM (
    SELECT col1, col2
    FROM table1
) AS x

查询失败但没有AS x结束.

编辑

使用SS2016时也需要它,不得不添加as t到最后.

 Select * into #result from (SELECT * FROM  #temp where [id] = @id) as t //<-- as t

Answer 3

最快的方法是使用"SELECT INTO"命令,例如

SELECT * INTO #TempTableName
FROM....

这将创建一个新表,您不必提前创建它.

Answer 4

你可以这样做:

INSERT INTO myTable (colum1, column2)
SELECT column1, column2 FROM OtherTable;

只需确保列匹配,数量与数据类型相同.

Answer 5

就个人而言，我需要一点点的努力来弄清楚如何使用它，它确实很棒。

IF(OBJECT_ID('tempdb..#TEMP') IS NOT NULL) BEGIN DROP TABLE #TEMP END
        SELECT *
            INTO #TEMP
            FROM (
            The query you want to use many times
            ) AS X

SELECT * FROM #TEMP WHERE THIS = THAT
SELECT * FROM #TEMP WHERE THIS <> THAT
SELECT COL1,COL3 FROM #TEMP WHERE THIS > THAT

DROP TABLE #TEMP

Answer 6

尝试这个：

SELECT *
INTO #Temp
FROM 
(select * from tblorders where busidate ='2016-11-24' and locationID=12
) as X

请在 x 中使用别名，以免脚本和结果失败。