走一个分层的树

Question

我希望能够通过分层集群"遍历"(迭代)(参见下图和代码).我想要的是:

1. 采用矩阵和最小高度的函数.在这个例子中说10.

   splitme <- function(matrix, minH){
       ##Some code
   }
   

2. 从顶部minH开始,每当有新的分割时开始切割.这是第一个问题.如何检测新的分裂以获得高度h.

3. 在这个特殊情况下h,有多少个集群？检索群集

   mycl <- cutree(hr, h=x);#x is that found h
   count <- count(mycl)# Bad code
   

4. 保存每个新矩阵的变量.这是另一个艰难的,x new矩阵的动态创建.所以也许一个带集群的函数做了需要做的事情(比较)并返回一个变量??

5. 继续3和4直到minH达到

数字

码

# Generate data
set.seed(12345)
desc.1 <- c(rnorm(10, 0, 1), rnorm(20, 10, 4))
desc.2 <- c(rnorm(5, 20, .5), rnorm(5, 5, 1.5), rnorm(20, 10, 2))
desc.3 <- c(rnorm(10, 3, .1), rnorm(15, 6, .2), rnorm(5, 5, .3))

data <- cbind(desc.1, desc.2, desc.3)

# Create dendrogram
d <- dist(data) 
hc <- as.dendrogram(hclust(d))

# Function to color branches
colbranches <- function(n, col)
  {
  a <- attributes(n) # Find the attributes of current node
  # Color edges with requested color
  attr(n, "edgePar") <- c(a$edgePar, list(col=col, lwd=2))
  n # Don't forget to return the node!
  }

# Color the first sub-branch of the first branch in red,
# the second sub-branch in orange and the second branch in blue
hc[[1]][[1]] = dendrapply(hc[[1]][[1]], colbranches, "red")
hc[[1]][[2]] = dendrapply(hc[[1]][[2]], colbranches, "orange")
hc[[2]] = dendrapply(hc[[2]], colbranches, "blue")

# Plot
plot(hc)

Answer 1

我认为您本质上需要的是树状图的共表相关系数。它会告诉您所有分裂点的高度。从那里您可以轻松地穿过树。我在下面进行了尝试，并将所有子矩阵存储到“子矩阵”列表中。这是一个嵌套列表。第一层是所有分裂点的子矩阵。第二层是来自分裂点的子矩阵。例如，如果您想要第一个分割点（灰色和蓝色簇）的所有子矩阵，则它应该是 submatrices[[1]]。如果您想要 submatrices[[1]] 中的第一个子矩阵（红色簇），则它应该是 submatrices[[1]][1]。

splitme <- function(data, minH){
  ##Compute dist matrix and clustering dendrogram
  d <- dist(data)
  cl <- hclust(d)
  hc <- as.dendrogram(cl)

  ##Get the cophenetic correlation coefficient matrix (cccm)
  cccm <- round(cophenetic(hc), digits = 0)

  #Get the heights of spliting points (sps)
  sps <- sort(unique(cccm), decreasing = T)

  #This list store all the submatrices
  #The submatrices extract from the nth splitting points
  #(top splitting point being the 1st whereas bottom splitting point being the last)
  submatrices <- list()

  #Iterate/Walk the dendrogram
  i <- 2 #Starting from 2 as the 1st value will give you the entire dendrogram as a whole
  while(sps[i] > minH){
    membership <- cutree(cl, h=sps[i]) #Cut the tree at splitting points
    lst <- list() #Create a list to store submatrices extract from a splitting point
    for(j in 1:max(membership)){
      member <- which(membership == j) #Get the corresponding data entry to create the submatrices
      df <- data.frame()
      for(p in member){
        df <- rbind(df, data[p, ])
        colnames(df) <- colnames(data)
        dm <- dist(df)
      }
      lst <- append(lst, list(dm)) #Append all submatrices from a splitting point to lst
    }
    submatrices <- append(submatrices, list(lst)) #Append the lst to submatrices list
    i <- i + 1
  }
  return(submatrices)
}