Lua:删除重复的元素

Question

我在lua有一张桌子

test = {1,2,4,2,3,4,2,3,4,"A", "B", "A"}

我想删除表中的所有重复元素.
输出应该是

test = {1,2,4,3,"A","B"}

编辑:

我的尝试:

> items = {1,2,4,2,3,4,2,3,4,"A", "B", "A"}
> flags = {}
> for i=1,table.getn(items)  do
if not flags[items[i]] then
      io.write(' ' .. items[i])
      flags[items[i]] = true
   end
>> end
 1 2 4 3 A B>

现在工作正常.感谢您的回答和评论.

Answer 1

类似于@Dimitry给出的示例,但只有一个循环

local test = {1,2,4,2,3,4,2,3,4,"A", "B", "A"}
local hash = {}
local res = {}

for _,v in ipairs(test) do
   if (not hash[v]) then
       res[#res+1] = v -- you could print here instead of saving to result table if you wanted
       hash[v] = true
   end

end