PLS-00103:遇到符号";" 当期待以下之一时:

Question

我的代码有什么问题

    SQL> declare
  2  mark number :=50;
  3  begin
  4  mark :=& mark;
  5  if (mark between 85 and 100)
  6  then
  7  dbms_output.put_line('mark is A ');
  8  else if (mark between 50 and 65) then
  9  dbms_output.put_line('mark is D ');
 10  else if (mark between 66 and 75) then
 11  dbms_output.put_line('mark is C ');
 12  else if (mark between 76 and 84) then
 13  dbms_output.put_line('mark is B');
 14  else 
 15  dbms_output.put_line('mark is F');
 16  end if;
 17  end;
 18  /
Enter value for mark: 65
old   4: mark :=& mark;
new   4: mark :=65;
end;
   *

第17行的错误:ORA-06550:第17行第4列:PLS-00103:遇到符号";" 期待以下之一时:if

Answer 1

问题是else和if是两个运算符.由于你打开一个新的'if',你需要一个相应的'end if'.

从而:

declare
mark number :=50;
begin
  mark :=& mark;
  if (mark between 85 and 100) then
    dbms_output.put_line('mark is A ');
  else 
    if (mark between 50 and 65) then
      dbms_output.put_line('mark is D ');
    else 
      if (mark between 66 and 75) then
        dbms_output.put_line('mark is C ');
      else 
        if (mark between 76 and 84) then
          dbms_output.put_line('mark is B');
        else 
          dbms_output.put_line('mark is F');
        end if;
      end if;
    end if;
  end if;
end;
/

或者你可以使用elsif:

declare
mark number :=50;
begin
  mark :=& mark;
  if (mark between 85 and 100)
    then
    dbms_output.put_line('mark is A ');
  elsif (mark between 50 and 65) then
    dbms_output.put_line('mark is D ');
  elsif (mark between 66 and 75) then
    dbms_output.put_line('mark is C ');
  elsif (mark between 76 and 84) then
    dbms_output.put_line('mark is B');
  else 
    dbms_output.put_line('mark is F');
  end if;
end;
/