dba*_*nes 4 javascript google-maps google-maps-api-3
好的,所以我正在学习谷歌地图API,我正试图根据长和拉特(谷歌地图如何与蓝点一起工作)获得实时移动点
不,除非我弄错了,看起来我必须绘制自己的圆圈并更新它的位置.
问题是我无法让圆圈得到更新.
这是我的代码:
var citymap = {};
citymap['chicago'] = {
center: new google.maps.LatLng(41.878113, -87.629798),
population: 2842518
};
var cityCircle;
function initialize() {
// Create the map.
var mapOptions = {
zoom: 4,
center: new google.maps.LatLng(37.09024, -95.712891),
mapTypeId: google.maps.MapTypeId.TERRAIN
};
var map = new google.maps.Map(document.getElementById('map-canvas'),
mapOptions);
// Construct the circle for each value in citymap.
// Note: We scale the population by a factor of 20.
for (var city in citymap) {
var populationOptions = {
strokeColor: '#fff',
strokeOpacity: 0.8,
strokeWeight: 2,
fillColor: '#fff',
map: map,
center: citymap[city].center,
radius: 50000,
};
// Add the circle for this city to the map.
cityCircle = new google.maps.Circle(populationOptions);
var a=0;
window.setInterval(function(){
var p = populationOptions.center;
var g = p.lat()+500;
var m = p.lng()+500;
cityCircle.setCenter(new google.maps.LatLng(g,m));
cityCircle.setRadius(a+=10);
}, 50);
}
}
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我真的很惊讶谷歌的api不只是暴露那个蓝色标记,你可以在需要时移动它.
您的更新功能不正确.任何有效的纬度+ 500都将不在地图上.更合理的数字是0.1度.另外,您应该使用cityCircle.getCenter()来代替populationOptions.center.
// Add the circle for this city to the map.
cityCircle = new google.maps.Circle(populationOptions);
var a=50000;
window.setInterval(function(){
var p = cityCircle.getCenter();
var g = p.lat()+0.1;
var m = p.lng()+0.1;
cityCircle.setCenter(new google.maps.LatLng(g,m));
cityCircle.setRadius(a+=10);
}, 500);
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