Preg_match从文本中排除单词

Question

我有字符串:

FirstWord word2 word3 wrongWord word4 lastWord

想要选择字符串开头FirstWord,结尾lastWord和不包含wrongWord.

我有第一个也是最后一个:

/ firstword(.*？)lastword/i

但排除wrongword不起作用.

尝试:

/ firstword(^ wrongWord*？)lastword/i

/ firstword ^((?! wrongWord).)*lastword/i

更像这样,但没有任何作用.

Answer 1

简单的以下是什么问题？

/^firstword ((?:(?!wrongword).)+) lastword$/i

看到 live demo

正则表达式:

^              the beginning of the string
 firstword     'firstword '
 (             group and capture to \1:
  (?:          group, but do not capture (1 or more times)
   (?!         look ahead to see if there is not:
    wrongword  'wrongword'
   )           end of look-ahead
   .           any character except \n
  )+           end of grouping
 )             end of \1
 lastword      ' lastword'
$              before an optional \n, and the end of the string