Arm*_*lak 2 asp.net textbox wcsf
我开始对一些完全平庸的事情感到不安:我没有从TextBox中获得用户输入:S
我这样做(aspx背后的代码):
protected void Page_Load(object sender, EventArgs e)
{
if (!this.IsPostBack)
{
this._presenter.OnViewInitialized();
}
this._presenter.OnViewLoaded();
txtBox1.Text = "blah";
}
protected void Button1_Click(object sender, EventArgs e)
{
//Do sth with txtBox1.Text but when I read it, it is still the same as when a loaded the page at Page_Load, So if I entered "blahblah" in the txtBox1 via browser the text I get when I debug or run is still "blah"
}
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和aspx
<%@ Page Language="C#" AutoEventWireup="true" CodeFile="InsertStudent.aspx.cs" Inherits="IzPT.Vb.Views.InsertStudent"
Title="VnosProfesorja" MasterPageFile="~/Shared/DefaultMaster.master" %>
<asp:Content ID="content" ContentPlaceHolderID="DefaultContent" Runat="Server">
<h1>Student</h1>
<p>
<table style="width:100%;">
<tr>
<td style="width: 139px">
Name</td>
<td>
<asp:TextBox ID="txtBox1" runat="server"></asp:TextBox>
</td>
</tr>
</table>
</p>
<p>
<asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="Save" />
</p>
</asp:Content>
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我还尝试使用DetailsView执行此操作并将其绑定到列表但是当我在编辑模式中读取值时,我遇到了同样的问题.
有任何想法吗?
您在每个Page_Load上将文本框Text属性设置为"blah".由于此时已加载ViewState,因此您将覆盖用户输入的任何值.
如果您只想将Text值设置一次,请确保将其放入if (!IsPostBack)检查中.
protected void Page_Load(object sender, EventArgs e)
{
if (!this.IsPostBack)
{
this._presenter.OnViewInitialized();
txtBox1.Text = "blah";
}
this._presenter.OnViewLoaded();
}
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