计算对Perl中的文件所做的更改

0 perl

我有一个名为"boot.log"的文件.我匹配此文件的模式,更改某些关键字,然后将它们写入名为"bootlog.out"的文件.我不确定如何计算所做的更改次数并将其打印到"bootlog.out".我很确定我需要使用foreeach循环和计数器,但我不知道在哪里.以及如何打印所做的更改.这是我到目前为止所拥有的......

open (BOOTLOG, "boot.log") || die "Can't open file named boot.log: $!";
open (LOGOUT, ">bootlog.txt") || die "Can't create file named bootlog.out: $!\n";

while ($_ = <BOOTLOG>)
{
    print $_;
    s/weblog/backupweblog/gi;
    s/bootlog/backupbootlog/gi;
    s/dblog/DBLOG/g;
    print LOGOUT $_;
}

close (LOGOUT) || die "Can't close file named bootlog.txt: $!\n";
close (BOOTLOG) || die "Can't close the file named boot.log: $!";
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jor*_*anm 5

替换正则表达式返回所做的替换次数.以下是代码的更新副本作为示例:

open (my $bootlog, '<', "boot.log")   || die "Can't open file named boot.log: $!";
open (my $logout, '>', "bootlog.txt") || die "Can't create file named bootlog.out: $!\n";

my $count = 0;
while (<$bootlog>)
{
    print $_;
    $count += s/weblog/backupweblog/gi;
    $count += s/bootlog/backupbootlog/gi;
    $count += s/dblog/DBLOG/g;
    print {$logout} $_;
}

close ($logout)  || die "Can't close file named bootlog.txt: $!\n";
close ($bootlog) || die "Can't close the file named boot.log: $!";
print "Total items changed: $count\n";
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