嗨,我正在使用jQuery创建一个输入数字增量,但没有成功,请你检查我的代码,并给我一个适当的指导
HTML
<div class="sp-quantity">
<div class="sp-minus fff"> <a class="ddd" href="#">-</a></div>
<div class="sp-input">
<input type="text" class="quntity-input" value="1">
</div>
<div class="sp-plus fff"> <a class="ddd" href="#">+</a></div>
</div>
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JS
$(".ddd").on("click", function () {
var $button = $(this);
var oldValue = $button.parent().find("input .quntity-input").val();
if ($button.text() == "+") {
var newVal = parseFloat(oldValue) + 1;
} else {
// Don't allow decrementing below zero
if (oldValue > 0) {
var newVal = parseFloat(oldValue) - 1;
} else {
newVal = 0;
}
}
$button.parent().find("input .quntity-input").val(newVal);
});
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找到输入的选择器不正确..quntity-input是一个孩子,.sp-quantity它在DOM的按钮上方两级,所以你需要使用closest()选择器,而不是parent.试试这个:
$(".ddd").on("click", function () {
var $button = $(this);
var oldValue = $button.closest('.sp-quantity').find("input.quntity-input").val();
if ($button.text() == "+") {
var newVal = parseFloat(oldValue) + 1;
} else {
// Don't allow decrementing below zero
if (oldValue > 0) {
var newVal = parseFloat(oldValue) - 1;
} else {
newVal = 0;
}
}
$button.closest('.sp-quantity').find("input.quntity-input").val(newVal);
});
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您还可以简化代码:
$(".ddd").on("click", function() {
var $button = $(this);
var $input = $button.closest('.sp-quantity').find("input.quntity-input");
$input.val(function(i, value) {
return +value + (1 * +$button.data('multi'));
});
});Run Code Online (Sandbox Code Playgroud)
.sp-quantity div { display: inline; }Run Code Online (Sandbox Code Playgroud)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="sp-quantity">
<div class="sp-minus fff"><a class="ddd" href="#" data-multi="-1">-</a></div>
<div class="sp-input">
<input type="text" class="quntity-input" value="1" />
</div>
<div class="sp-plus fff"><a class="ddd" href="#" data-multi="1">+</a></div>
</div>Run Code Online (Sandbox Code Playgroud)
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