在保存模型时,正在处理ember-data中的自定义服务器端错误

Dee*_*tha 6 ember.js grails-2.0 ember-data

保存模型时是否有正确的方法来处理自定义错误?举个例子,假设我的模型只有两个属性"name"和"value".当我这样做时:

var myModel = this.get('store').createRecord('myModel', {"name": "someName", "value": "someValue"});
myModel.save().then(function() {
    //if success
    //server responded with {"myModel:{"id":1,"name":"someName","value":"someValue"}"}
},function() {
    //if failure
    //server responded with {"error":"some custom error message"}
    //BUT HOW TO CATCH THIS AND POSSIBLY REMOVE THE MODEL FROM THE STORE

});
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解决此问题的一种方法是进行额外的ajax调用以检查名称是否唯一,然后执行保存.我只是想知道这里最好/最优雅的方法是什么.

谢谢,迪

编辑:我认为在groovy中为事物的服务器端提供更多上下文可能会有所帮助.所以这里是:

在我的控制器中我有:

def create() {

    try {
        newRow = someService.create(params)
        render someService.list(newRow) as JSON//returns data in format needed by ember-data
    }
    catch (ValidationException ex) {
        def errors = ["errors":[]]

        ex.errors.allErrors.each{
            if(it.arguments[0] == "fieldName" && it.code=="constrantViolated"){
                errors.errors.push(["field":it.arguments[0],"message":"some custom message"])
            }
        }
        //I am using 422 here because of post in http://stackoverflow.com/questions/7996569/can-we-create-custom-http-status-codes
        render(status: 422, contentType: 'JSON', text: (errors as JSON))
    }

}
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然后在我的余烬控制器中:

    var myModel = self.get('store').createRecord('myModel ', myModelDataInJSON);
myModel .save().then(function () {
        //if success
                },
    function (response) {
        myModel .deleteRecord();
        var errors = $.parseJSON(response.responseText);
        for (var key in errors.errors) {
            //do something
        }
    });
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Kin*_*n2k 8

deleteRecord 将删除记录.

myModel.save().then(function(response) {
  //if success
  //server responded with {"myModel:{"id":1,"name":"someName","value":"someValue"}"}
},function(response) {
  //if failure
  //server responded with {"error":"some custom error message"}
  //BUT HOW TO CATCH THIS AND POSSIBLY REMOVE THE MODEL FROM THE STORE
  if(response.error=='no good'){
    myModel.deleteRecord();
  }

});
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  • 这就是我现在的表现,但我不喜欢它开始显示记录并在服务器应答后将其删除.有没有办法等待服务器答案显示持久记录? (2认同)