Java SWT Composite 1 px填充

Question

我在我的父Composite上使用了一个GridLayout,并希望终止在渲染对象时创建的1px填充.要使此部件工作,要更改的参数是什么？我的复合材料就是这样呈现的

final Composite note = new Composite(parent,SWT.BORDER);
GridLayout mainLayout = new GridLayout(1,true);
mainLayout.marginWidth = 0;
mainLayout.marginHeight = 0;
mainLayout.verticalSpacing = 0;
mainLayout.horizontalSpacing = 0;
note.setLayout(mainLayout);

图片:

Answer 1

SWT.BORDER导致你的问题.在Windows 7上,它将绘制2px,一个灰色和一个白色的边框.使用SWT.NONE摆脱边框的完全.

如果你真的想要一个1px灰色边框,你可以为你的父母添加一个Listenerfor SWT.Paint,Composite并使它绘制一个边框GC:

public static void main(String[] args)
{
    final Display display = new Display();
    Shell shell = new Shell(display);
    shell.setLayout(new GridLayout(1, false));

    final Composite outer = new Composite(shell, SWT.NONE);
    outer.setLayoutData(new GridData(SWT.FILL, SWT.FILL, true, true));
    GridLayout layout = new GridLayout(1, false);
    layout.marginHeight = 0;
    layout.marginWidth = 0;
    outer.setLayout(layout);

    Composite inner = new Composite(outer, SWT.NONE);
    inner.setBackground(display.getSystemColor(SWT.COLOR_WHITE));
    inner.setLayoutData(new GridData(SWT.FILL, SWT.FILL, true, true));

    shell.addListener(SWT.Paint, new Listener()
    {
        public void handleEvent(Event e)
        {
            e.gc.setBackground(display.getSystemColor(SWT.COLOR_WIDGET_BORDER));
            Rectangle rect = outer.getBounds();
            Rectangle rect1 = new Rectangle(rect.x - 1, rect.y - 1, rect.width + 2, rect.height + 2);
            e.gc.setLineStyle(SWT.LINE_SOLID);
            e.gc.fillRectangle(rect1);
        }
    });

    shell.pack();
    shell.open();
    while (!shell.isDisposed())
    {
        if (!display.readAndDispatch())
            display.sleep();
    }
    display.dispose();
}

看起来像这样:

这里有绿色背景: