如果另一个表中不存在id,则从表中删除

Question

我想删除types无法找到的id ,types_photos但我不知道如何实现这一目标.id_type在types_photos是一样id的types.这是表的结构如何:

CREATE TABLE IF NOT EXISTS `types` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `id_user_added` int(11) DEFAULT '0',
  `id_user_edited` int(11) DEFAULT '0',
  `data_name` text NOT NULL,
  `data_name_seo` text NOT NULL,
  `data_type` enum('tag','equipment','search') NOT NULL,
  `datetime_added` datetime NOT NULL,
  `datetime_edited` datetime NOT NULL,
  `ipaddress_added` text NOT NULL,
  `ipaddress_edited` text NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `id` (`id`)
)

CREATE TABLE IF NOT EXISTS `types_photos` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `id_user_added` int(11) DEFAULT '0',
  `id_user_edited` int(11) DEFAULT '0',
  `id_type` int(11) DEFAULT '0',
  `id_photo` int(11) DEFAULT '0',
  `datetime_added` datetime NOT NULL,
  `datetime_edited` datetime NOT NULL,
  `ipaddress_added` text NOT NULL,
  `ipaddress_edited` text NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `id` (`id`)
)

所以,我的问题是; 如何删除types无法找到的所有ID types_photos？

Answer 1

DELETE FROM types 
WHERE id NOT IN (
  SELECT ID FROM types_photos
)