如何从单个脚本中打开两个控制台

Question

除了脚本自己的控制台(什么都不做)我想打开两个控制台并打印变量con1和con2在不同的控制台,我怎么能实现这一点.

con1 = 'This is Console1'
con2 = 'This is Console2'

我不知道如何实现这一点,并花了几个小时尝试使用模块,subprocess但没有运气.顺便说一句,我在窗户上.

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编辑:

请问threading模块做的工作？还是multiprocessing需要？

例如:

Answer 1

如果您不想重新考虑问题并使用诸如@ Kevin的答案之类的GUI,那么您可以使用subprocess模块同时启动两个新控制台并在打开的窗口中显示两个给定的字符串:

#!/usr/bin/env python3
import sys
import time
from subprocess import Popen, PIPE, CREATE_NEW_CONSOLE

messages = 'This is Console1', 'This is Console2'

# open new consoles
processes = [Popen([sys.executable, "-c", """import sys
for line in sys.stdin: # poor man's `cat`
    sys.stdout.write(line)
    sys.stdout.flush()
"""],
    stdin=PIPE, bufsize=1, universal_newlines=True,
    # assume the parent script is started from a console itself e.g.,
    # this code is _not_ run as a *.pyw file
    creationflags=CREATE_NEW_CONSOLE)
             for _ in range(len(messages))]

# display messages
for proc, msg in zip(processes, messages):
    proc.stdin.write(msg + "\n")
    proc.stdin.flush()

time.sleep(10) # keep the windows open for a while

# close windows
for proc in processes:
    proc.communicate("bye\n")

这是一个不依赖的简化版本CREATE_NEW_CONSOLE:

#!/usr/bin/env python
"""Show messages in two new console windows simultaneously."""
import sys
import platform
from subprocess import Popen

messages = 'This is Console1', 'This is Console2'

# define a command that starts new terminal
if platform.system() == "Windows":
    new_window_command = "cmd.exe /c start".split()
else:  #XXX this can be made more portable
    new_window_command = "x-terminal-emulator -e".split()

# open new consoles, display messages
echo = [sys.executable, "-c",
        "import sys; print(sys.argv[1]); input('Press Enter..')"]
processes = [Popen(new_window_command + echo + [msg])  for msg in messages]

# wait for the windows to be closed
for proc in processes:
    proc.wait()

Answer 2

您可以使用两个Tkinter Text小部件来获得两个控制台之类的东西.

from Tkinter import *
import threading

class FakeConsole(Frame):
    def __init__(self, root, *args, **kargs):
        Frame.__init__(self, root, *args, **kargs)

        #white text on black background,
        #for extra versimilitude
        self.text = Text(self, bg="black", fg="white")
        self.text.pack()

        #list of things not yet printed
        self.printQueue = []

        #one thread will be adding to the print queue, 
        #and another will be iterating through it.
        #better make sure one doesn't interfere with the other.
        self.printQueueLock = threading.Lock()

        self.after(5, self.on_idle)

    #check for new messages every five milliseconds
    def on_idle(self):
        with self.printQueueLock:
            for msg in self.printQueue:
                self.text.insert(END, msg)            
                self.text.see(END)
            self.printQueue = []
        self.after(5, self.on_idle)

    #print msg to the console
    def show(self, msg, sep="\n"):
        with self.printQueueLock:
            self.printQueue.append(str(msg) + sep)

#warning! Calling this more than once per program is a bad idea.
#Tkinter throws a fit when two roots each have a mainloop in different threads.
def makeConsoles(amount):
    root = Tk()
    consoles = [FakeConsole(root) for n in range(amount)]
    for c in consoles:
        c.pack()
    threading.Thread(target=root.mainloop).start()
    return consoles

a,b = makeConsoles(2)

a.show("This is Console 1")
b.show("This is Console 2")

a.show("I've got a lovely bunch of cocounts")
a.show("Here they are standing in a row")

b.show("Lorem ipsum dolor sit amet")
b.show("consectetur adipisicing elit")

结果:

Answer 3

我不知道它是否适合你，但你可以使用Windowsstart命令打开两个Python解释器：

from subprocess import Popen
p1 = Popen('start c:\python27\python.exe', shell=True)
p2 = Popen('start c:\python27\python.exe', shell=True)

当然有一个问题，现在Python以交互模式运行，这不是你想要的（你也可以传递文件作为参数，该文件将被执行）。

在 Linux 上，我会尝试创建命名管道，将文件名传递给 python.exe 并将 python 命令写入该文件。“也许”它会起作用；）

但我不知道如何在 Windows 上创建命名管道。Windows API ...（自行填写）。