为什么这个elif语句会抛出错误？

Question

class TheBridge(Scene):

def enter(self):
    print "You burst into the bridge with the bomb"
    print "There are a number of gothons standing about"
    print "and looking scared of the bomb you currently have underneath your arm"
    print "They look nervous about what you are going to do"

    action = raw_input("> ")


    if action == "Throw the bomb":
        print "You throw the bomb at the gorcons on the bridge"
        print "They pure and utter crap themselves and pull out their laser blasters and shhot you dead"
        print "at least the bomb will kill the gorcons, you die a hero"
        return 'death'

    elif action == "Put the bomb down slowly":
        print "You pull you laser blaster from your holster and point it at the bomb"
        print " You very slowly set the bomb on the ground and move backwards"
        print "You then jump back through the door and start firing your gun at the"
        print "lock and you blast it so the gorcons can't escape"
        print "You then procede to try and find an escape pod"
        return 'escape_pod'

    else:    
        print "DOES NOT COMPUTE"
        return "the_bridge"

由于某种原因,它会抛出语法错误.也许我是一个完全白痴,看不到令人眼花缭乱的明显事物.绝对不是间距或缩进或类似的东西,因为我已经检查过.

有任何想法吗？

错误信息:

  File "ex43.py", line 131
    elif action == "Put the bomb down slowly":
       ^
SyntaxError: invalid syntax`

Answer 1

你正在混合制表符和空格(这里复制的帖子当然可以).

运行您的代码python -tt并修复发现的任何问题.

最好用空格替换所有选项卡,并将编辑器配置为自动执行.