我有这个问题:
set @last_uid = 0;
set @last_tm = '00:00';
set @last_vid = 0;
SELECT v.*,
CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN
if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE
if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
ORDER BY timestamp DESC, visitorid
Run Code Online (Sandbox Code Playgroud)
我试图在WHERE子句中使用newVisitID列,如下所示:
WHERE newVisitID <=5
Run Code Online (Sandbox Code Playgroud)
这给了我错误:
#1054 - Unknown column 'newVisitID' in 'where clause'
Run Code Online (Sandbox Code Playgroud)
谁能帮我解决这个问题?
您不能在WHERE子句中引用别名,但可以在HAVING以下位置引用它们:
SELECT v.*,
CASE WHEN @last_uid = visitorid AND cast( @last_tm as datetime) >= subtime( timestamp, '01:00' )
THEN
if( (@last_tm := timestamp ), @last_vid, @last_vid)
ELSE
if( (@last_uid := visitorid) + (@last_vid := @last_vid+1) +(@last_tm := timestamp ),@last_vid, @last_vid )
END AS newVisitID
FROM visits v
HAVING newVisitID <- 5
ORDER BY timestamp DESC, visitorid
Run Code Online (Sandbox Code Playgroud)